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3 years ago

Drag the tiles to the correct boxes to complete the pairs.

Mathematics

1 answer:

marishachu [46]3 years ago

5 0

Answer:

security deposit advance payment to protect the landlord against damage to the property

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Porfa ayudenme con este ejercicio.

Daniel [21]

D) La camisa roja y el pantalon negro

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3 years ago

Read 2 more answers

PLZ HELP ME GEOMETRY<br> question is below

konstantin123 [22]

The missing justification is for the statement that three angles add to a particular angle. The appropriate choice is ...

... c. Angle Addition Postulate

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3 years ago

Ms. Clandestine is planning to take her study group on a field trip to an amusement park. The regular cost is $25 per person. Th

DiKsa [7]

Question 1:

Multiply the regular price by the number of people (x)

Y = 25x

Question 2:

Multiply the special rate by number of people(x) and add the cost of the room:

Y = 15x + 150

Question 3:

Replace x with a positive value and solve for y, which will be larger than the x value

Answer (15,375)

Question 4:

This means for 15 people the total cost for the special rate would be $375

3 0

3 years ago

What is the answer to this question?<br> I am confused.

olga nikolaevna [1]

Answer:

y=88 x=42

Step-by-step explanation:

Since the total measurments of one triangle have to equal 180 and one angle is already 50, and the angle on the oppisite side of the y angle is 90 the only logical number for y would be 88. Hope this helped :)

5 0

3 years ago

AYUDA CON ESTO!!! ALGUIEN PORFAVOR

Gre4nikov [31]

Answer:

Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

$Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds$

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

$\frac{200}{60} = \frac{10}{3} \approx 3.33$ loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

$\frac{200}{65} = \frac{40}{13} \approx 3.08$ loops per minute

then the period is:

$\frac{13}{40} =0.325\,\,\,minutes$

Therefore runner B has the smaller period

8 0

3 years ago