How do you find the nth to the quadratic sequence of 3,8,15,24,35

1 answer:

4 0

Having the first term of the sequence

a(0)=3

a(1)=3+5=8

We realized that

a(1)=a(0)+2⋅2+1

We also have :

a(2)=a(1)+2⋅3+1=8+7=15

a(3)=a(2)+2⋅4+1=15+9=24

From above we can realize that each term is the sum of the previous

term and 2*(sequence coefficient added to 1) and 1

So the nth term will be:

a(n)=a(n−1)+2⋅(n+1)+1

You might be interested in

Help!!!! 20 points!!!!!!’

Gnoma [55]

Answer:

option c is the correct answer

first take y raised to the power 4 common then cancel its power by y raised to the power 3

you get your answer

3 0

3 years ago

What is the average (arithmetic mean) of eleven consecutive integers? (1) the average of the first nine integers is 7. (2) the a

laiz [17]

Since eleven is odd, there must be a centra element, which in this case is the sixth. So, we can write 11 consecutive integers as

$x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5$

Since the arithmetic mean is the sum of the values, divided by how many they are, we have

$M = \dfrac{x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5}{11} = \dfrac{11x}{11} = x$

So, the mean of 11 consecutive integers is the 6th integer.

4 0

3 years ago

PLEASE THESE 2 HELPPPPPPPPPPPP

nirvana33 [79]

Answer:

c and g

Step-by-step explanation:

6 0

3 years ago

Which set of parametric equations represents the graph of the function shown?

Molodets [167]

Stupid get yo brain to work BOIIIIIJ

5 0

3 years ago

Solutions for y=-x^2-5x+12

nydimaria [60]

Answer: y = -(x+5/2)^2+73/4

Step-by-step explanation:

3 0

2 years ago