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Anettt [7]
3 years ago
9

Consider the functions below.

Mathematics
1 answer:
Anestetic [448]3 years ago
3 0

Answer:

NONE simply because they both are not possible

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Solve equation by factoring.
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Hi ;-)

x^2+6x-10=30 \ \ /-30\\\\x^2+6x-40=0\\\\a=1, \ b=6, \ c=-40\\\\\Delta=b^2-4ac=6^2-4\cdot1\cdot(-40)=36+160=196\\\\\sqrt{\Delta}=\sqrt{196}=14\\\\x_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-6-14}{2}=\boxed{-10}\\\\x_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-6+14}{2}=\boxed4

8 0
3 years ago
Put these decimals in order starting with the smallest.
iVinArrow [24]

Answer:

8.008

8.018

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<em><u>If this helped, please consider picking this answer as the Brainliest Answer. Thank you!</u></em>

3 0
2 years ago
Read 2 more answers
I need the answers for both a and b so thats why 61 points are up for grab
kodGreya [7K]

Answer:

Step-by-step explanation:

From the picture attached,

a). Triangle in the figure is ΔBCF

b). Since, L_1 and L_2 are the parallel lines and m is a transversal line,

   m∠FBC = m∠BFG [Alternate interior angles]

   Since,  L_1 and L_2 are the parallel lines and n is a transversal line,

   m∠BCF = m∠CFE [Alternate interior angles]

   By triangle sum theorem in ΔBCF

   m∠FBC + m∠BCF + m∠BFC = 180°

   From the properties given above,

   m∠BFG + m∠CFE + m∠BFC = 180°

   m∠GFE = 180°

Therefore, angle GFE is the straight angle that will be useful in proving that the sum of the measures of the interior angles of the triangle is 180°.

5 0
2 years ago
6 in<br> 24 in<br><br> I don’t get this at all and I have trouble with math
nekit [7.7K]
What’s the full question?
6 0
2 years ago
#17: If the area of a rectangle measures 20 square inches, the side lengths must
Karo-lina-s [1.5K]
A counterexample could be 2 inches and 10 inches.
4 0
2 years ago
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