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suter [353]
3 years ago
6

What is the smallest of 3 consecutive odd numbers if the product of the smaller two integers is 3 less than 6 times the largest

integer?
Mathematics
1 answer:
pochemuha3 years ago
3 0

Answer:

7,9,11

Step-by-step explanation:

Let first number is x, second number is (x+2) and third number is (x+4).

ATQ,

The product of the smaller two integers is 3 less than 6 times the largest integer.

x(x+2) = 6(x+4)-3

x² + 2x = 6x+24-3

x² + 2x = 6x+21

x² + 2x -6x -21=0

x²-4x -21=0

It is a quadratic equation whose solution is :

x = -3 and x = 7

First number = 7

Second number = 9

Third number = 11

Hence, this is the required ssolution.

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Use Euclid's division algorithm to find the HCF of 441, 567, 693
Illusion [34]
Let a = 693, b = 567 and c = 441

Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under

693 = 567 x 1 + 126
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Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63

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Jobisdone [24]

Answer:

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