What is the smallest of 3 consecutive odd numbers if the product of the smaller two integers is 3 less than 6 times the largest
integer?
1 answer:
Answer:
7,9,11
Step-by-step explanation:
Let first number is x, second number is (x+2) and third number is (x+4).
ATQ,
The product of the smaller two integers is 3 less than 6 times the largest integer.
x(x+2) = 6(x+4)-3
x² + 2x = 6x+24-3
x² + 2x = 6x+21
x² + 2x -6x -21=0
x²-4x -21=0
It is a quadratic equation whose solution is :
x = -3 and x = 7
First number = 7
Second number = 9
Third number = 11
Hence, this is the required ssolution.
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