Question

Tanya drove 3 1/2 hours and used 1/3 tank of gas.

Answer 1

Hey this was my attempt to help explain the answer

Answer 2

Answer: $5\frac{1}{4}\ hours$

Step-by-step explanation:

Given: Tanya drove car in $\frac{1}{3}$ tank of gas=   $3\frac{1}{2}$ hours $=\frac{7}{2}$ hours

Tanya drove car in a full tank of gas = $\frac{\frac{7}{2}}{\frac{1}{3}}=\frac{7}{2}\times3=\frac{21}{2}$ hours

Tanya drove car in $\frac{1}{2}$ tank of gas=$\frac{21}{2}\times\frac{1}{2}=\frac{21}{4}=5\frac{1}{4}\ hours$

Hence, Tanya drove $5\frac{1}{4}\ hours$car in $\frac{1}{2}$ tank of gas.