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anastassius [24]

3 years ago

11

If y’all help me I’ll mark you as brainliest:) this geometry

2 answers:

HACTEHA [7]3 years ago

7 0

Answer:

78 degrees

Step-by-step explanation:

180 - 102 = 78

marin [14]3 years ago

6 0

Answer:

78°

Step-by-step explanation:

Straight line has 180° so

180°-102°= 78°

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WILL MARK AS BRAINIEST!!!!!!! In this triangle, which of the following is true?

prisoha [69]

Answer:

D

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the 2 given angles from 180

x = 180° - (90 + 35)° = 180° - 125° = 55°

----------------------------------------------------------

Since the triangle is right use the cosine ratio to solve for b

cos35° = $\frac{adjacent}{hypotenuse}$ = $\frac{b}{20}$

Multiply both sides by 20

20 × cos35° = b, hence

b = 16.38 ( to 2 dec. places )

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for every 5 pounds of pasta served , 15 people can be fed. how many people can be fed with 4 pounds of pasta?

Sidana [21]

Answer:

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Step-by-step explanation:

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3 years ago

With purchased a pair of jeans they were orginally 24 cent but were on sale for one third off the total price. How much did he s

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3 years ago

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Find the volume of each pyramid or come. Round to the nearest tenth if necessary.

Naya [18.7K]

QUESTION 1

The given pyramid has a square base.

The volume of this square pyramid is given by;

$V=\frac{1}{3}\times l^2\times h$

where $l=5ft$ is the length of a side of the square base.

and $h=8ft$ is the height of the pyramid.

We substitute the values into the formula to get;

$V=\frac{1}{3}\times 5^2\times 8 ft^3$

$V=66.7 ft^3$

QUESTION 2

The given pyramid has a rectangular base.

The volume of this rectangular pyramid is given by;

$V=\frac{1}{3}\times l\times b\times h$

where $l=7cm$ and w=4cm are the length and width of a side of the rectangular base.

and $h=8cm$ is the height of the pyramid.

We substitute the values into the formula to get;

$V=\frac{1}{3}\times 7\times 4\times 8cm^3$

QUESTION 3

The given pyramid has a rectangular base.

The volume of this rectangular pyramid is given by;

$V=\frac{1}{3}\times l\times b\times h$

where $l=10in.$ and w=8in are the length and width of a side of the rectangular base respectively.

There is a right triangle created inside this pyramid that can help us find the height of this pyramid.

Notice that the base of this right triangle is half the width of the rectangular base (4in.) and the hypotenuse is 14in.

We need to use Pythagoras Theorem to find the height of this pyramid.

$h^2+4^2=14^2$

$h^2+16=196$

$h^2=196-16$

$h^2=180$

$h=\sqrt{180}$

$h=6\sqrt{5}in.$

We substitute the values into the formula to get;

$V=\frac{1}{3}\times 10\times 8\times6\sqrt{5}in^3$

$V=160\sqrt{5}in^3$

$V=357.8in^3$

QUESTION 4

The radius of the base of the given cone is 12m.

The height of the cone is 25m.

The volume of a cone is calculated using the formula;

$V=\frac{1}{3}\pi r^2h$

We substitute the given values to get;

$V=\frac{1}{3}\pi 12^2\times 25m^3$

$V=3769.9m^3$

QUESTION 5

The given cone has diameter 14yd.

The radius is half the diameter, r=7yd

The radius(7yd), the height (h), and the slant height(25yd being the hypotenuse) form a right triangle.

We apply the Pythagoras Theorem again to get;

$h^2+7^2=25^2$

$h^2+49=625$

$h^2=625-49$

$h^2=576$

$h=\sqrt{576}$

$h=24$

The height of the cone is 24yd.

The volume of a cone is calculated using the formula;

$V=\frac{1}{3}\pi r^2h$

We substitute the given values to get;

$V=\frac{1}{3}\pi 7^2\times 24yd^3$

$V=1231.5yd^3$

QUESTION 6

The height of the given cone is 18mm.

The radius can be calculated using the tangent ratio.

$\tan(66\degree)=\frac{18}{r}$

$r=\frac{18}{\tan(66\degree)}$

$r=8.0141yd$

The volume of a cone is calculated using the formula;

$V=\frac{1}{3}\pi r^2h$

We substitute the given values to obtain;

$V=\frac{1}{3}\pi 8.0141^2\times 18mm^3$

$V=151.1mm^3$

7 0

3 years ago