Answer:
Rider 1 does one round in 15 min, and will complete another in each consecutive multiple of 15 min
Rider 2 does one round in 18 min, and will complete another in each consecutive multiple of 18 min
Assuming that they start together, they will complete another round together in a time that is both multiples of 15min and 18 min.
Then we need to find the smallest common multiple between 15 and 18.
To smallest common multiple between two numbers, a and b, is equal to:
a*b/(greatest common factor between a and b).
Now, the greatest common factor between 15 and 18 can be found if we write those numbers as a product of prime numbers, such as:
15 = 3*5
18 = 2*3*3
The greatest common factor is 3.
Then the smallest common multiple will be:
(15*18)/3 = 90
This means that after 90 mins, they will meet again at the starting place.
Given the sequence:
6, 10, 14, 18,...
We will find the 75th term
The given sequence is an arithmetic sequence
Because there is a constant common differnce
d = 18 - 14 = 14 - 10 = 10 - 6 = 4
The first term = a = 6
The general formula of the arithmetic sequence is as follows:

Where: n is the nth term
To find the 75th term, substitute with n = 75 and a = 6, d = 4

So, the answer will be the 75th term = 302
Answer:
A. A(n) = 150 • (0.74)^n–1 ; 33.29 cm
Step-by-step explanation:
This is a geometric sequence.
a%5B1%5D=1.5m=150cm, r=0.74
The formula is
a%5Bn%5D=a%5B1%5Dr%5E%28n-1%29
Just substitute a1 = 150cm and r = 0.74
a%5Bn%5D=150%280.74%29%5E%28n-1%29
That's the rule.
For the second part, substitute n = 6
cm.
Answer:
i believe more than 1 ounce let me know if im wrong
Step-by-step explanation: