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2 years ago

Which expression is equivalent to 9c + 12d + 2c

Mathematics

1 answer:

Alexxx [7]2 years ago

7 0

Answer:

B. 11c + 12d

Step-by-step explanation:

Given

9c + 12d + 2c

Combine the like terms

= 11c + 12d

Hope it will help :)

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Help me pls pls pls

9966 [12]

Answer:

Step-by-step explanation:

Plug in a x-value and see which table matches the result. Plug in 1.

f(x) = 7 - 4.5x

f(1) = 7 - 4.5(1)

f(1) = 7 - 4.5

f(1) = 2.5

The table that matches an input of 1 with an output of 2.5 is B.

6 0

3 years ago

Consider the following differential equation to be solved by undetermined coefficients. y(4) − 2y''' + y'' = ex + 1 Write the gi

kompoz [17]

Answer:

The general solution is

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2}$

Step-by-step explanation:

Step :1:-

Given differential equation y(4) − 2y''' + y'' = e^x + 1

The differential operator form of the given differential equation

$(D^4 -2D^3+D^2)y = e^x+1$

comparing f(D)y = e^ x+1

The auxiliary equation (A.E) f(m) = 0

$m^4 -2m^3+m^2 = 0$

$m^2(m^2 -2m+1) = 0$

$(m^2 -2m+1) this is the expansion of (a-b)^2$

$m^2 =0 and (m-1)^2 =0$

The roots are m=0,0 and m =1,1

complementary function is $y_{c} = (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x$

Step 2:-

The particular equation is $\frac{1}{f(D)} Q$

P.I = $\frac{1}{D^2(D-1)^2} e^x+1$

P.I = $\frac{1}{D^2(D-1)^2} e^x+\frac{1}{D^2(D-1)^2}e^{0x}$

P.I = $I_{1} +I_{2}$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x + \frac{1}{D^{2} } e^{0x}$

$\frac{1}{D} means integration$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x = \frac{1}{2D} \int\limits {x^2e^x} \, dx$

applying in integration u v formula

$\int\limits {uv} \, dx = u\int\limits {v} \, dx - \int\limits ({u^{l}\int\limits{v} \, dx } )\, dx$

$I_{1}$ = $\frac{1}{D^2(D-1)^2} e^x$

$\frac{1}{2D} (e^x(x^2)-e^x(2x)+e^x(2))$

$\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

$I_{2}$ $= \frac{1}{D^2(D-1)^2}e^{0x}$

$\frac{1}{D} \int\limits {1} \, dx= \frac{1}{D} x$

again integration $\frac{1}{D} x = \frac{x^2}{2!}$

The general solution is $y = y_{C} +y_{P}$

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2!}$

3 0

3 years ago

What are the solutions to the quadratic equation 2x^2-8x-24=0

Vinvika [58]

2x^2 - 8x - 24

First, we can factor a 2 out of this expression to simplify it.

2(x^2 - 4x - 12)

Now, we can try factoring this two ways: by using the quadratic formula, or by using the AC method.

We're gonna try using the AC method first.

List factors of -12.

1 * -12

-1 * 12

2 * -6

-2 * 6 (these digits satisfy the criteria.)

Split the middle term.

2(x^2 - 2x + 6x - 12)

Factor by grouping.

2(x(x - 2) + 6(x - 2)

Rearrange terms.

<h3>(2)(x + 6)(x - 2) is the fully factored form of the given polynomial.</h3>

7 0

3 years ago

Read 2 more answers

X^3+3x^5=x5 what's the missing expression

shutvik [7]

x3+3x5=x53x5+x3=x5Subtract x^5 from both sides.3x5+x3−x5=x5−x52x5+x3=0Factor left side of equation.x3(2x2+1)=0Set factors equal to 0.x3=0‌‌ or ‌‌2x2+1=0x=0

3 0

3 years ago

Read 2 more answers

Number 2 to 4 I don’t understand it.

Natalka [10]

All estimating problems make the assumption you are familar with your math facts, addition and multiplication. Since students normally memorize multiplication facts for single-digit numbers, any problem that can be simplified to single-digit numbers is easily worked.

2. You are asked to estimate 47.99 times 0.6. The problem statement suggests you do this by multiplying 50 times 0.6. That product is the same as 5 × 6, which is a math fact you have memorized. You know this because
.. 50 × 0.6 = (5 × 10) × (6 × 1/10)
.. = (5 × 6) × (10 ×1/10) . . . . . . . . . . . by the associative property of multiplication
.. = 30 × 1
.. = 30

3. You have not provided any clue as to the procedure reviewed in the lesson. Using a calculator,
.. 47.99 × 0.6 = 28.79 . . . . . . rounded to cents

4. You have to decide if knowing the price is near $30 is sufficient information, or whether you need to know it is precisely $28.79. In my opinion, knowing it is near $30 is good enough, unless I'm having to count pennies for any of several possible reasons.

5 0

3 years ago