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Sati [7]
3 years ago
11

7. Which of the following is an example of a

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
5 0

Answer: c

Step-by-step explanation:

Klio2033 [76]3 years ago
3 0
By looking at the answer a is eliminated by default since it is not between 6 and 7 which also eliminates e. now you’re left with b and c and you have to remember the definition of an irrational number (in short, it’s a number that never ends) which would leave you with c
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What is the vertical asymptote of this function?
liraira [26]

Answer:

D

Step-by-step explanation:

If y = log x is the basic function, let's see the transformation rule(s):

Then,

1. y = log (x-a) is the original shifted a units to the right.

2. y = log x + b is the original shifted b units up

Hence, from the equation, we can say that this graph is:

** 2 units shifted right (with respect to original), and

** 10 units shifted up (with respect to original)

<u><em>only, left or right shift affects vertical asymptotes.</em></u>

Since, the graph of y = log x has x = 0 as the vertical asymptote and the transformed graph is shifted 2 units right (to x = 2), x = 2 is the new vertical asymptote.

Answer choice D is right.

7 0
3 years ago
Given x-intercepts of -3 and 2 find and equation for a graph that goes through both points. (You do NOT have to graph the equati
lesya [120]

Answer:

1? lllllllllllll the answer is 1 I think

6 0
3 years ago
If you roll a standard six sided dice, what is the probability you will roll a four?
astra-53 [7]

Answer:

1/6

Step-by-step explanation:

There are 6 sides on a dice. Every time you roll you you will have one of those sides. So it is a 1 in 6 chance of you getting 4, meaning that the answer to this problem is 1/6

7 0
3 years ago
How many different seven-letter sequences can be formed from the letters a, a, a, a, a, b, c?
Kaylis [27]

If b is in the first position then c can be in any 1 of the remaining 6 positions.

If we start with ab then the letter c can be in any one of 5 positions and  if we have aab there are 4 possible positions for c and so on.

So the total number of possible sequences where b comes first = 6+5+4+3+2+1 =  21.

The same argument applies when c comes before b  so that gives us 21 ways also.

So the answer is 2 *21 = 42 different sequences.

A more direct way of doing  this  is to use factorials:-

answer = 7! / 5!     =  7 * 6 = 42.

 ( We divide by 5!   because of the 5 a's.)

4 0
3 years ago
Given f(x)= (4x+1)/3 solve for f^-1(3)
nirvana33 [79]
I hope this helps you

7 0
3 years ago
Read 2 more answers
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