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Jobisdone [24]
3 years ago
6

Explain how to find the reference angle for 1,406 degrees. Find the reference angle.

Mathematics
1 answer:
nataly862011 [7]3 years ago
3 0
The reference angle is the smallest angle between the terminal ray and the x-axis.
 1406° mod 360° = 326°
The reference angle will be 360° -326° = 34°.
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Supposed U = {-10, -9, -8, -7, -6, -5, -4, -3, -2, -1} is the universal set and K = {-10, -8, -6, -4, -2}. What is K’?
Ilia_Sergeevich [38]

Answer:

-9

Step-by-step explanation:

-9,

3 0
3 years ago
Aubrey is making cone-shaped hats for a birthday party. She mistakenly thinks that she will need about 104 square inches of pape
jenyasd209 [6]

Answer:

C. About 75 in²; Aubrey found the surface area of the cone and included the base.

Step-by-step explanation:

In the questions above we were given the following:

Cone with

Diameter(D) = 6 inches

Slant height (l) = 8 inches.

Aubrey made an error in her calculation.

She found the Total Surface area of the cone using the formula:

Total Surface Area of a cone = πrl + πr²

= πr(l + r)

The Total surface area of a cone is the calculated as Sum of the curved surface area of a cone and the base of the cone.

Where:

Curved surface area of the cone is calculated as = πrl

Base of a cone is calculated as = πr²

Where r = radius of the cone

l = slant height of the cone

In the question, we were given

slant height(l) = 8 inches.

radius = Diameter ÷ 2 = 6÷2 = 3 inches.

Using π = 3.14

Surface area = 3.14 × 3(8+3)

= 9.42 × 11

Surface area = 103.62 in²

Approximately to the nearest inch = 104 in² or 104 square inches.

But this answer is WRONG.

The RIGHT FORMULA Aubrey should have used is

Curved Surface Area or the Lateral Area of a Cone = πrL

slant height(l) = 8 inches.

radius = Diameter ÷ 2 = 6÷2 = 3 inches.

Using π = 3.14

Curved Surface Area of a Cone = πrL

= 3.14 × 3 inches × 8 inches

= 75.36 square inches or 75.36in²

Approximately to the nearest inch = 75 square inches or 75 in².

This is the correct answer.

The error Aubrey made was she calculated the Total surface area of the cone which includes the base of the cone instead of calculating the curved surface area of the cone only.

Hence, from the above calculation , we can see that Option C "About 75 in²; Aubrey found the surface area of the cone and included the base" is the correct option.

5 0
3 years ago
What is the solution to the system of equations? 3x + 10y = -47 5x- 7y = 40<br>Please and thank u
anastassius [24]

Answer:

x=1, y=-5

Step-by-step explanation:

Given equations are:

3x+10y=-47\ Eqn\ 1\\and\\5x-7y=40\ Eqn\ 2

In order to solve the equation

Multiplying Eqn 1 by 5 and eqn 2 by 3 and subtracting them

So,

Eqn 1 becomes

15x+50y=-235

Eqn 2 becomes

15x-21y=120

Subtracting 2 from a

15x+50y - (15x-21y) = -235-120

15x+50y-15x + 21y = -355

71y = -355

y = -355/71

y =-5

Putting y= -5 in eqn 1

3x+10(-5) = -47

3x -50 = -47

3x = -47+50

3x = 3

x = 3/3

x = 1

Hence the solution is:

x=1, y=-5

5 0
3 years ago
Read 2 more answers
Select the type of equations Consistent Equivalent Inconsistent
Vikki [24]

Answer:

21 is the answer for that

5 0
3 years ago
A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced.
zzz [600]

Answer:

CI=(66.54,78.46)                                  

Step-by-step explanation:

Given : A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced. The mean yield of the 10 batches is 72.5% and the standard deviation is 5.8%. Assume the yields are independent and approximately normally distributed.

To find : A 99% confidence interval for the mean yield when the new catalyst is used ?

Solution :

Let X be the yield of the batches.

We have given, n=10 , \bar{X}=72.5\% , s=5.8%

Since the size of the sample is small.

We will use the student's t statistic to construct a 995 confidence interval.

\bar X\pm t_{n-1,\frac{\alpha}{2}}\frac{s}{\sqrt n}

From the t-table with 9 degree of freedom for \frac{\alpha}{2}=0.005

t_{n-1,\frac{\alpha}{2}}=t_{9,0.005}

t_{n-1,\frac{\alpha}{2}}=3.250

The 99% confidence interval is given by,

CI=72.5 \pm 3.25\frac{5.8}{\sqrt{10}}

CI=72.5 \pm 5.96

CI=(72.5+5.96),(72.5-5.96)

CI=(66.54,78.46)

8 0
3 years ago
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