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ValentinkaMS [17]
3 years ago
13

I WILL GIVE BRAINLIEST IF YOU GET IT RIGHT!!!!

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
3 0

9514 1404 393

Answer:

  (a)  In triangles APD and BPC; AD = BC

Step-by-step explanation:

We're not concerned with triangle APB, eliminating the last 2 choices.

We're not concerned with sides AP and BP, as they're not sides of the square, eliminating the second choice.

The choice that makes any sense in the proof is ...

  In triangles APD and BPC; AD = BC

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If 3x is one factor of 3x^2-9x, what is the other factor?
Rudik [331]
The answer is:  " (x² − 3) " .
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Explanation:
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Given:  3x² <span>− 9x ;  factor out a "3x" ; 
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   </span>→  3x (x² − 3) ;
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     The answer is:  " (x² − 3) " .
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7 0
3 years ago
What is the fraction 18/24 reduced to its lowest terms?
WINSTONCH [101]
<em>First, find the greatest common factor (GCF) of the numerator and denominator.</em>

<u>Factors of 18</u>: 1, 2, 3, 6, 9, 18
<u>Factors of 24</u>: 1, 2, 3, 4, 6, 8, 12, 24
<u>Common Factors</u>: 1, 2, 3, 6
<u>GCF</u>: 6

<em>Now, divide the numerator by 6 and the denominator by 6.</em>

18 ÷ 6 = 3
24 ÷ 6 = 4

<em>Set these as your new numerator and denominator.</em>

\frac{3}{4}

The answer is (b).

8 0
3 years ago
Read 2 more answers
Fr33 points 38/827. 72/727
Virty [35]

Answer:

thx

Step-by-step explanation:

:D:D:D

7 0
3 years ago
Read 2 more answers
I neeeeeeed Help please!
pochemuha

Answer:

i ask your teacher

Step-by-step explanation:

ask your teacher instead of asking for answers

4 0
3 years ago
Can someone please help I really need these points
spayn [35]

Given:

Two chords intersect each other inside the circle.

To find:

The value of x.

Solution:

According to intersecting chords theorem, if two chords intersect each other inside the circle, then the product of two segments of one chord is equal to  the product of two segments of second chord.

In the given circle,

AE\times CE=BE\times DE

(3x-11)\times (5x-4)=(x+2)\times (-x+17)

15x^2-12x-55x+44=-x^2+17x-2x+34

15x^2-67x+44+x^2-15x-34=0

16x^2-82x+10=0

Divide both sides by 2.

8x^2-41x+5=0

Splitting the middle term, we get

8x^2-40x-x+5=0

8x(x-5)-1(x-5)=0

(8x-1)(x-5)=0

Using zero product property, we get

(8x-1)=0 or (x-5)=0

x=\dfrac{1}{8} or x=5

For x=\dfrac{1}{8}, the side AE is negative. So, x=\dfrac{1}{8} is not possible.

Therefore, the required solution is x=5.

6 0
3 years ago
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