3 years ago

I need help please.

Mathematics

2 answers:

Leviafan [203]3 years ago

8 0

7y^2 + 2y + 3 - 6y^2 - 3y - 4
(7-6)y^2 + (2-3)y + (3-4)
y^2 - y -1
C.

avanturin [10]3 years ago

4 0

7y2+2y2+3-6y2-3y2-4
7y2+6y2+2y-3y+3-4
y2-y-1

You might be interested in

What is the slope of the line with the equation of y= 3x that passes through the points (2, 6)?

SashulF [63]

Answer:

is there a picture?

Step-by-step explanation:

5 0

2 years ago

What’s the correct answer for this?

Aleksandr [31]

Answer:

Step-by-step explanation:

52units

5 0

3 years ago

Read 2 more answers

A hemispherical dome of radius 50 feet is to be given 3 coats of paint, each of which is 1/100 inch thick. Use linear approximat

Alchen [17]

Answer:

Step-by-step explanation:

5 0

3 years ago

Salaries of 49 college graduates who took a statistics course in college have a mean, x overbar, of $ 65 comma 300. Assuming a

Molodets [167]

Answer: $60,540< \mu$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\overline{x}-z^*\dfrac{\sigma}{\sqrt{n}}< \mu$

, where $\sigma$ = Population standard deviation.

n= sample size

$\overline{x}$ = Sample mean

z* = Critical z-value .

Given : $\sigma=\$17,000$

n= 49

$\overline{x}= \$65,300$

Two-tailed critical value for 95% confidence interval = $z^*=1.960$

Then, the 95% confidence interval would be :-

$65,300-(1.96)\dfrac{17000}{\sqrt{49}}< \mu$

$=65,300-(1.96)\dfrac{17000}{7}< \mu$

$=65,300-4760< \mu$

$=60,540< \mu$

Hence, the 95% confidence interval for estimating the population mean $(\mu)$ :

$60,540< \mu$

7 0

3 years ago

Just want to make sure

stepan [7]

<span>3x + 3y = 3 hope this helped</span>

4 0

3 years ago

Read 2 more answers