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IRINA_888 [86]
3 years ago
12

Someone please help me in algebra

Mathematics
1 answer:
Verdich [7]3 years ago
8 0
Is this the only problem you need help on ? Or is there more ?
You might be interested in
Help!!!!
Lyrx [107]
I believe the answer is the first one because it contains a negative fraction and in the chart some of the numbers are negative
8 0
3 years ago
If f(1)=2f(1)=2 and f(n)=f(n-1)^2-n
katrin [286]

Answer:

f(4)=-3

Step-by-step explanation:

f(1)=2

f(n)=f(n-1)^2-n

If n=2

f(2)=f(2-1)^2-2

f(2)=f(1)^2-2

f(2)=2^2-2

f(2)=4-2

f(2)=2

If n=3

f(3)=f(3-1)^2 - 3

f(3)=f(2)^2 - 3

f(3)=2^2-3

f(3)=4-3

f(3)=1

if n=4

f(4)=f(4-1)^2 - 4

f(4)=f(3)^2 - 4

f(4)=1^2 - 4

f(4)=1-4

f(4)=-3

6 0
3 years ago
A local little league has a total of 85 players, of whom 20% are left-handed. How many left-handed players are there?
tankabanditka [31]

Answer:

68 i think

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
98 POINTS PLEASE HELP! How does the graph of f(x) = (x − 1)^2 relate to the basic function f(x) = x^2?
Paha777 [63]

When you graph the two functions given, the graph B) shift 1 unit to the right.

Graph the two functions, see attached pictures:




<em>~Rise Above the Ordinary</em>


8 0
3 years ago
Read 2 more answers
A computer system requires that passwords contain at least one digit. if eight characters are generated at random, and each is e
KIM [24]
Figure this out as though no digits are present. You can choose 8 of the 26 letters and that's it.
26^8 [you can allow repeating letters]  =  2.088 * 10^11
The total number of ways that can be chosen with letters and digits intermixed = 36^8

The probability of getting no numbers is 26^8 / 36^8 or (26/36)^8 = 0.07402
So the probability that there were be at least one digit is
1 - 0.07402 = 0.92598
6 0
3 years ago
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