3 years ago

Please guysss help me with this question!!!!!

Mathematics

1 answer:

Masja [62]3 years ago

3 0

Its D) amplitude=2 and midline y=2

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Why does the problem <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7By%5E2-5%7D%7By%5E4-81%7D%2B%5Cfrac%7B4%7D%7By%5E4-81%7D%5

adelina 88 [10]

$\bf \cfrac{y^2-5}{y^4-81}+\cfrac{4}{y^4-81}\implies \cfrac{y^2-5+4}{y^4-81}\implies \cfrac{y^2-1}{y^4-81}\\\\
-----------------------------\\\\
\textit{now recall your }\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
\textit{and keep in mind that }
\begin{cases}
1^2=1\\
1^3=1\\
1^{1,000,000}=1\\
----------\\
81=9^2\\
9=3^2
\end{cases}\\\\
$

$\bf -----------------------------\\\\
thus
\\\\\\
\cfrac{y^2-1^2}{(y^2)^2-9^2}\implies \cfrac{(y-1)(y+1)}{(\underline{y^2-9})(y^2+9)}
\\\\\\
\cfrac{(y-1)(y+1)}{\underline{(y-3)(y+3)}(y^2+9)}$

would be a factored version of it

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3 years ago

-12a + 13b - 32 please help me

Studentka2010 [4]

Answer: 12a+ 13b

Step-by-step explanation:

7 0

3 years ago

What is eight and nineteen thousandths in decimal form

Xelga [282]

8.019!
Hope this helps!

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