Question

Use quadratic formula to find both solutions to the quadratic equation given below . 3x^2-5x-1=0

Answer 1

Answer:

$x1=\frac{5+\sqrt{37}} {6}$

$x2=\frac{5-\sqrt{37}} {6}$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^{2} -5x-1=0$  

so

$a=3\\b=-5\\c=-1$

substitute in the formula

$x=\frac{5(+/-)\sqrt{(-5)^{2}-4(3)(-1)}} {2(3)}$

$x=\frac{5(+/-)\sqrt{37}} {6}$

$x1=\frac{5+\sqrt{37}} {6}$

$x2=\frac{5-\sqrt{37}} {6}$

Answer 2

Answer:

x=-1

x=1\4

Step-by-step explanation: