I need help on math on how to solve a linear equation. So how do you solve (x-2)+(2x+5).

Mathematics

1 answer:

saveliy_v [14]3 years ago

4 0

So, put your "x's" together first and then your intercepts. That should answer your question :)

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A rectangular school banner has a length of 40 inches and a width of 24 inches. A sign is made that is similar to the school ban

e-lub [12.9K]

Answer:

The answer is 960

Step-by-step explanation:all you would have to do is multiply the lenth times width. 40x24=960

4 0

3 years ago

Im running out of time Somebody help me out please

kobusy [5.1K]

Answer:

3, 4, and 5

Step-by-step explanation:

To put it simply, 3 + 4 + 5 = 12 and the numbers are consecutive, next to each other.

The method:

The three consecutive numbers could be called x, x + 1, and x + 2 and we know that x + x + 1 + x + 2 = 12

This can be simplified to 3x + 3 = 12. Next, subtract 3 from both sides to get 3x = 9. Now, divide both sides by 3 to get x = 3.

This means that the first number is 3 and the other numbers are 4 (3 + 1) and 5 (3 + 2).

Hope this helps!

8 0

3 years ago

Read 2 more answers

Solve 2(b − 3) ≥ 3(3 − b) and describe the graph of the solution. Show all your work.

solong [7]

Answer:

$\large\boxed{b\geq3\to b\in[3,\ \infty)}$

Step-by-step explanation:

$2(b-3)\geq3(3-b)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\(2)(b)+(2)(-3)\geq(3)(3)+(3)(-b)\\\\2b-6\geq9-3b\qquad\text{add 6 to both sides}\\\\2b-6+6\geq9+6-3b\\\\2b\geq15-3b\qquad\text{add}\ 3b\ \text{to both sides}\\\\2b+3b\geq15-3b+3b\\\\5b\geq15\qquad\text{divide both sides by 5}\\\\\dfrac{5b}{5}\geq\dfrac{15}{5}\\\\b\geq3$