Groups of 2, I don't know anything else. Sorry, I hope it helped though
N in this problem is equal to 15.
(2/3)- students working on math
6-total students
(2/3) of 6 students+= (2/3)x6 = (12/3) = 4
Answer:
6
(4×n²) + (4×n¹) + (5×n^0) = 173
4n² + 4n + 5 = 173
4n² + 4n = 168
divide through by 4
n² + n - 42 = 0
n² + 7n - 6n - 42= 0
(n + 7)(n - 6) = 0
n = -7 or 6
but the solution is 6 since base is not negative.
