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denis-greek [22]
3 years ago
13

Jose wandered 4 kilometers at 2 kilometers per hour. How long did jose wnader?

Chemistry
1 answer:
Anton [14]3 years ago
7 0
8 kilometer? is that right or explain to me pls.
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The rate of reaction was measured during a chemical reaction. After the first 3 seconds, the rate of reaction was 1.8 x10-6 M/s.
avanturin [10]

Answer:

The rate would be lower and the concentration of reactants would be lower.

Explanation:

The rate of a chemical reaction depends on the rate constant and the concentration of reactants.

For Ex:

For a reaction experimentally given by A + B ----> C + D

Rate = k[A][B]

where k is the rate constant

          [A] = concentration of reactant A

          [B] = concentration of reactant B

As the reaction proceeds,the concentration of reactant decrease and concentration of products increase.Rate constant k depends only on temperature and activation energy.Hence it will remain constant throughout the reaction assuming that reaction is carried out at constant temperature and pressure.

Hence rate will depend only on concentration of reactants and hence decrease with decrease in concentration of reactants.

8 0
3 years ago
Iron has a density of 7.86 g/cm3. Calculate the volume (in dL) of a piece of iron having a mass of 4.07 kg . Note that the densi
elena-s [515]

Answer:

The volume of the piece of iron is 5.18dL.

Explanation:

The density (ρ) is equal to the mass (m) divided the volume (V).

\rho = \frac{m}{V}

If we rearrange it, we have:

V=\frac{m}{\rho }

To express the volume in dL we will need the following relations:

  • 1 dL = 0.1 L
  • 1 kg = 10³ g
  • 1 cm³ = 1 mL
  • 1mL = 10⁻³L

Then,

\rho = \frac{7.86g}{cm^{3} } .\frac{1cm^{3} }{1mL} .\frac{1mL}{10^{-3}L } .\frac{1kg}{10^{3}g } =7.86kg/L

Finally,

V=\frac{m}{\rho }=\frac{4.07kg}{7.86 kg/L} =0.518L.\frac{1dL}{0.1L} =5.18dL

5 0
4 years ago
Read 2 more answers
A first-order reaction has a half-life of 16.7 s . How long does it take for the concentration of the reactant in the reaction t
andrew11 [14]

It takes 33.4 s for the concentration of A to fall to one-fourth of its original value.

A <em>half-life</em> is the time it takes for the concentration to fall to half its original value.

Assume the initial concentration is 1.00 mol/L. Then,

\text{1.00 mol/L }\stackrel{\text{1st half-life }}{\longrightarrow}\text{ 0.50 mol/L } \stackrel{\text{ 2nd half-life }}{\longrightarrow}\text{0.25 mol/L}\\

The concentration drops to one-fourth of its initial value in two half-lives.

∴ Time = 2 × 16.7 s = 33.4 s

5 0
3 years ago
19.
solmaris [256]

Answer:

В.  No, because the mass of the reactants is less than the mass of the products.

Explanation:

Chemical equation:

NaBr + Cl₂      →      2NaCl + Br₂

The given equation is not balanced because number of moles of sodium and bromine atoms are less on reactant side while more on the product side.

There are one mole of sodium and one mole of bromine atom on left side of equation while on right side there are 2 moles of bromine and 2 moles of sodium atom are present. The number of moles of chlorine atoms are balanced.

Balanced chemical equation:

2NaBr + Cl₂      →      2NaCl + Br₂

Now equation is balanced. Number of moles of sodium , chlorine and bromine atoms are equal on both side.

5 0
3 years ago
When 412.5 g of calcium carbonate react with 521.9 g of aluminum fluoride, how many
LekaFEV [45]
Answer
321.8 g CaF2
321.5 g Al2(CO3)3
5 0
3 years ago
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