Answer:
Step-by-step explanation:
To solve for the inverse, we need to switch the variables and solve for y.
Note that f(x) is the same as y or in other words, the output.
f(x) = 3x + 5
y = 3x + 5
~Switch variables
x = 3y + 5
~Subtract 5 to both sides
x - 5 = 3y
~Divide 3 to everything
1/3x - 5/3 = y
~Flip
y = 1/3x - 5/3
Best of Luck!
Answer:
A) sin θ = 3/5
B) tan θ = 3/4
C) csc θ = 5/3
D) sec θ = 5/4
E) cot θ = 4/3
Step-by-step explanation:
We are told that cos θ = 4/5
That θ is the acute angle of a right angle triangle.
To find the remaining trigonometric functions for angle θ, we need to find the 3rd side of the triangle.
Now, the identity cos θ means adjacent/hypotenuse.
Thus, adjacent side = 4
Hypotenuse = 5
Using pythagoras theorem, we can find the third side which is called opposite;
Opposite = √(5² - 4²)
Opposite = √(25 - 16)
Opposite = √9
Opposite = 3
A) sin θ
Trigonometric ratio for sin θ is opposite/hypotenuse. Thus;
sin θ = 3/5
B) tan θ
Trigonometric ratio for tan θ is opposite/adjacent. Thus;
tan θ = 3/4
C) csc θ
Trigonometric ratio for csc θ is 1/sin θ. Thus;
csc θ = 1/(3/5)
csc θ = 5/3
D) sec θ
Trigonometric ratio for sec θ is 1/cos θ. Thus;
sec θ = 1/(4/5)
sec θ = 5/4
E) cot θ
Trigonometric ratio for cot θ is 1/tan θ. Thus;
cot θ = 1/(3/4)
cot θ = 4/3
Antoine sleep 8 hours in a day
Answer:
1) is not possible
2) P(A∪B) = 0.7
3) 1- P(A∪B) =0.3
4) a) C=A∩B' and P(C)= 0.3
b) P(D)= 0.4
Step-by-step explanation:
1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4 . Thus the maximum possible value of P(A∩B) is 0.4
2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by
P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7
P(A∪B) = 0.7
3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3
4) the event C that the selected student has a visa card but not a MasterCard is given by C=A∩B' , where B' is the complement of B. Then
P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3
the probability for the event D=a student has exactly one of the cards is
P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4
''Two one-step equationsx + 7 = 10x = 7-7 = 10 - 7x = 3
y + 47 = 20y = 47 - 47 = 20 - 47y = 27
Two equations that contains fractions + 2 + 3 = 55/5 = or 1
+ 12 + 7 = 1919/20 =
Distributive property2x - 4(+4) = 10(+4)2x - 16 = 402x - 16 + 16 = 40 + 162x = 5656 ÷ 2 = 28x = 28
Decimalsx = 1.2 + 7.8 ÷ 3(5)1.2 + 7.8 = 99 ÷ 3 = 33 x 5 = 1515.0
One real-world problem that is solved by an equationJohnny deposits $2,000 into a bank account. If the interest rate is 5% per month how much will he have gained in interest in 6 years?5% of 2,000 is 100100 x 12 = 1,2001,200 x 6 = 7,200Johnny would gain $7,200 in 6 years''
hope this helps
