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choli [55]
3 years ago
8

What is this plz help

Mathematics
2 answers:
siniylev [52]3 years ago
8 0

Answer:

The answer to the question is A.

Paul [167]3 years ago
4 0
Answer: A
yes yes yes it’s A
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Need help<br> Question in the screenshot below<br> NO spam<br> Please show your work
Alja [10]
<h3>Answer:   x = 6</h3>

======================================================

Work Shown:

\log_{4}(x+10)+\log_{4}(x-2)=\log_{4}(64)\\\\\log_{4}\left((x+10)(x-2)\right)=\log_{4}(64)\\\\(x+10)(x-2)=64\\\\x^2-2x+10x-20=64\\\\x^2-2x+10x-20-64=0\\\\

x^2+8x-84=0\\\\(x+14)(x-6)=0\\\\x+14=0 \ \text{ or } \ x-6=0\\\\x=-14 \ \text{ or } \ x=6\\\\

Those are the possible solutions, but plugging x = -14 back into the original equation will lead to an error. So we rule x = -14 out

x = 6 works as a solution however

3 0
3 years ago
Is 3 squared times 4 squared equal 12 squared ? Evaluate each side of the equation to explain your answer.
Nikolay [14]

Answer:

Nopes 3²+4²≠12²

Step-by-step explanation:

12²=144

3²+4²=

9+16=25

25≠144

To make it easier to see exactly WHY 3²+4²≠12² you can spread out the numbers in the equation.

(3·3)+(4·4)≠(12·12)

When solving equations you use PEMDAS (Parenthesis Exponents Multiplication Division Addition Subtraction). You have to solve in THAT ORDER.

7 0
3 years ago
Read 2 more answers
While solving an equation for x lewis is left with the equation 2=4. Explain why lewis can be certain that the equation does not
olga nikolaevna [1]

Answer: You do not have x alone on one side, therefore, you can be certain the equation has no solution!!

Step-by-step explanation: In order for the equation to have a solution it must look like this:

x= and some number

3 0
3 years ago
As a part of lesson on motion students observed a cart rolling at <br> a constant
AlekseyPX

Answer:

follow me for right answer

8 0
3 years ago
Write the equation of the line through (−5,3) and:
Lelechka [254]

Answer:

<h2>a) x + y = -2</h2><h2>b) x - y = -8</h2><h2>c) 3x - 5y = -30</h2><h2>d) 5x + 3y = -16</h2>

Step-by-step explanation:

Equation of line with slope m and passing through (x₁,y₁) is given by

               y - y₁ = m ( x -x₁)

            (x₁,y₁) = (−5,3)

a) Parallel to x = −1

    Slope , m = -1

           y - y₁ = m ( x -x₁)

           y - 3 = -1 ( x -(-5))

           y -3 = -x - 5

           x + y = -2

b) Perpendicular to x = −1.

   Slope of line x Slope of perpendicular line = -1

   Slope of line x -1 = -1

    Slope , m = 1

           y - y₁ = m ( x -x₁)

           y - 3 = 1 ( x -(-5))

           y -3 = x + 5

           x - y = -8

c) Parallel to y = 3 / 5 x + 2

    Slope , m = 3/5

           y-y_1=m(x-x_1)\\\\y-3=\frac{3}{5}(x-(-5))\\\\5y-15=3x+15\\\\3x-5y=-30

                 3x - 5y = -30

d) Perpendicular to y = 3 / 5 x + 2

Slope of line x Slope of perpendicular line = -1

   Slope of line x 3/5 = -1

    Slope , m = -5/3

     y-y_1=m(x-x_1)\\\\y-3=\frac{-5}{3}(x-(-5))\\\\3y-9=-5x-25\\\\5x+3y=-16

                 5x + 3y = -16

3 0
3 years ago
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