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aev [14]
3 years ago
15

Solve the equation for 0° ≤ x ≤ 90°. Round to the nearest degree. 8cotθ + 3 = 5

Mathematics
1 answer:
galina1969 [7]3 years ago
5 0

<u><em>Answer:</em></u>

θ = 76°

<u><em>Explanation:</em></u>

<u>The given equation is:</u>

8 cotθ + 3 = 5

8 cotθ = 5-3

8 cotθ = 2

cot θ = \frac{2}{8} = \frac{1}{4}

<u>Now, we find θ</u>

We know that the cot function is the inverse of the tan function.

The tan of an angle is positive in the first and third quadrants, therefore, the cot will be <u>positive</u> in the <u>first and third quadrants</u> as well

<u>Now, we are given the condition:</u>

0° ≤ x ≤ 90°

<u>Therefore, we know for sure that our angle is in the first quadrant</u>

θ = cot⁻¹(\frac{1}{4}) = 75.96° = 76° to the nearest degree

Hope this helps :)

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Answer:

x ≥ 4

Step-by-step explanation:

–4(8 – 3x) ≥ 6x – 8

Distribute

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-32 +12x-6x ≥ 6x-6x – 8

-32 +6x  ≥  – 8

Add 32 to each side

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The correct answer is option B which is the actual product is about StartFraction 1 over 18 EndFraction less than the estimate.

<h3>What are fractions?</h3>

The fraction is defined as the division of the whole part into an equal number of parts. here we have the following information Vassil rounded to the nearest half to estimate the product of Five-eighths and StartFraction 8 over 9 EndFraction.

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1 year ago
Built around 2600 BCE, the Great Pyramid of Giza in Egypt is 485 ft high (due to erosion, its current height is slightly less) a
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Step-by-step explanation:

From figure above, using triangle ratio

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Consider a slice volume Vslice= (755.5y/485)^2∆y; recall density =150lb/ft^3

Force slice = 150*755.5^2.y^2.∆y/485^2

From figure 2 in the attachment work done for elementary sclice

Wslice= 150.755.5^2.y^2.∆y.(485-y)/485^2

= (150*755.5^2*y^2)(485-y)∆y/485

To calculate the total work we integrate from y=0 to y= 485

Ie W=[ integral of 150*755.5^2 *y^2(485-y)dy/485] at y=0 and y= 485

Integrating the above

W= 150*755.5^2/485[485*y^3/3-y^4/4] at y= 0 and y=485

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3 years ago
You invested money in two funds. Last year, the first fund paid a dividend of 8% and the second a dividend of 5%, and you receiv
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You invested 11000 in in 2st fund and 9000 in 2nd fund

<h3><u>Solution:</u></h3>

Given that, You invested money in two funds.  

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This year, the first fund paid a 12% dividend and the second only 2%, and you received a total of $1500.

Let the amount in Fund I be $x and amount in Fund II be $ y

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