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Drupady [299]
3 years ago
12

Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution:

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
5 0
It would have an infinite amount of solutions.
Change each equation into y=mx+b form and then do system of equations.
jekas [21]3 years ago
5 0

Answer: infinitely many solutions

Step-by-step explanation:

-x+3y=-1 | :(-1)

x-3y=1

x-3y=1

x-3y=1

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Answer:

See Explanation

Step-by-step explanation:

Your question is incomplete, as the equations or graph or table(s) were not given.

However, I'll give a general way of solving this.

Take for instance, the equations are:

y = \frac{4}{3}x - 1

y = \frac{2}{3}x - \frac{1}{2}

To do this, we start by equating both equations.

y = y

i.e.

\frac{4}{3}x - 1= \frac{2}{3}x - \frac{1}{2}

Collect Like Terms

\frac{4}{3}x - \frac{2}{3}x= 1 - \frac{1}{2}

Take LCM

\frac{4x- 2x}{3}= \frac{2 - 1}{2}

\frac{2x}{3}= \frac{1}{2}

Cross Multiply

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4x = 3

Make x the subject

x = \frac{3}{4}

Substitute 3/4 for x in y = \frac{4}{3}x - 1

y = \frac{4}{3} * \frac{3}{4} - 1

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Hence:

(x,y) = (\frac{3}{4},0)

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Answer:

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<h3><u>For </u><u>Verification</u>;</h3>

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