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makvit [3.9K]
3 years ago
10

How do you solve this system of linear equation by substitution x-3y=-12y=2x+9

Mathematics
1 answer:
Ainat [17]3 years ago
6 0
Finding x:
If y=2x+9, substitute y into the equation x-3y=-12.
You will get:  x-3(2x+9)=-12
Now, distribute:  x-6x-27=-12
Add like terms:  -5x-27=-12
Add 27 to both sides:  -5x=15
Divide both sides by -5:  x=-3

Now, substitute this value of x into the equation to find y:  y=2(-3)+9
Multiply:  y=-6+9
Add:  y=3

Here is the solution:  (x,y)=(-3,3)

Hope this explanation helped!




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Answer: 3

Step-by-step explanation:

Let say x the width of the tank,

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3 years ago
Please help with these two problems. Show work
MissTica

Answer:

For the first one, it is 1150. For the second one, it is 2460.

Step-by-step explanation:

Think of 23 x 50 as (20 x 50) + (3 x 50).

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Read 2 more answers
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mr_godi [17]

Answer:


Step-by-step explanation:

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y = (-8/5) x

This is a nasty piece of work and it depends on your grade level. If you are below grade 8, you are not encouraged to think of a constant of proportionality as less than 0.

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What Is the absolute value of y=2|x+3|-3
ArbitrLikvidat [17]

Answer:

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Step-by-step explanation:


8 0
3 years ago
Five sixth-grade classes collected canned food for the local food bank. Each class collected a different number of cans. Use the
tekilochka [14]

Answer:

308, 398, 421, 433, 570

Step-by-step explanation:

To start we know the smallest is 308 cans, so that is the first class.

Next, it says the range is 262. The range is maximum minus the minimum. Since we know the minimum(308), that means 308 + 262 = 570 and 570 is the maximum or the class with most collected cans.

Then, it says the median or the middle number is 421, the middle number in a class is 3. So, the third class collected a total of 421 cans.

After that, it says the two classes in the three hundred, or the first and second class, has a total of 706 cans. So, if we do 706 - 308 we get the second class. Which collected 398 cans.

Finally, it says the total all the class collected is 2130. So, if we add all the values we have know and subtract it from the total of all the class we get the missing class or the fourth class. So, 308 + 398 + 421 + 570 = 1697, and 2130 -1697 = 433. Which the fourth class.

Least to greatest:

308

398

421

433

570

3 0
3 years ago
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