Write the equation in slope intercept form of the line that is perpendicular to y=-3x+7 and passes through the point (6,-4)

Mathematics

2 answers:

seropon [69]3 years ago

5 0

The answer to this question is Y= -1/3 - 2

Gre4nikov [31]3 years ago

4 0

The equation is y = -1/3x-2.

To determine the equation, I remembered that for a equation to be perpendicular of another, the original slope will be the reciprocal. So, -3 will turn into -1/3. Then I written the equation y=mx + b. I wrote out -4 = -1/3 (6) + b because I plugged in the x and y values. Then I solved for b. The result I got for b was -2.

After solving for b, the equation I found was y= -1/3x-2

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Which property was used to simplify the expression? (3z)^2 = 3^2z^2 = 9z^2

svet-max [94.6K]

One of the product rules for exponents was used.
$(ab)^{c}=a^{c}b^{c}$

Or, you can consider that the definition of an exponent and the associative and commutative properties of multiplication were used.
$(3z)^{2}\\=(3z)(3z)\\=3\cdot 3\cdot z\cdot z\\=3^{2}z^{2}\\=9z^{2}$