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Sidana [21]
3 years ago
7

Drag steps in the given order to evaluate this expression. -2(-3 + 5) - 4

Mathematics
1 answer:
coldgirl [10]3 years ago
5 0

Answer:

-8

Step-by-step explanation:

Using PEDMAS( parentheses,exponents, division, multiply, addition, subtraction) to solve the Problem

-2(-3 + 5) - 4

First add (-3+5) because they are in parentheses.

-2(-3 + 5) - 4

=-2*2-4

Next, multiply -2*2.

-4-4

subtract -4-4

-8

-2(-3 + 5) - 4 is equal to -8

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Enrollment in a school district is currently 1250 students and is decreasing at approximately 3% per year. Enter the number of y
FromTheMoon [43]

Answer: the number of years is 7.3 years

Step-by-step explanation:

We would apply the formula for exponential decay which is expressed as

A = P(1 - r)^ t

Where

A represents the population after t years.

t represents the number of years.

P represents the initial population.

r represents rate of growth.

From the information given,

P = 1250

A = 1000

r = 3% = 3/100 = 0.03,

Therefore

1000 = 1250(1 - 0.03)^t

1000/1250 = (0.97)^t

0.8 = 0.97^t

Taking log of both sides, it becomes

Log 0.8 = tLog 0.97

- 0.0969 = - 0.0132t

t = - 0.0969/- 0.0132t

t = 7.3 years

4 0
3 years ago
2 cups of raisins for every 12 cups, how many cups if only 8 cups of raisins
svp [43]
Use a proportion.

cups of raisins to cups = cups of raisins to cups

2/12 = 8/x

2x = 8 * 12

x = 4 * 12

x = 48

Answer: 48 cups
4 0
4 years ago
Weight gain during pregnancy. In 2004, the state of North Carolina released to the public a large data set containing informatio
pychu [463]

Answer:

1. B. H0: μ1−μ2=0, HA: μ1−μ2≠0

2. z=1.2114

3. P-value=0.2257

4. Do not reject H0

Step-by-step explanation:

We have to perfomr an hypothesis test to see if there is strong evidence that there is a significant difference between the two population means.

The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2\neq0

Being μ1 the mean average gain for younger mothers and μ2 the mean average gain for mature mothers.

(NOTE: we are comparing means, not proportions, as it is the random variable is the weight gain).

As we are claiming "strong evidence", the level of significance will be 0.01.

For younger mothers, the sample size is n1=840, the sample mean is 30.7 and  the sample standard deviation is s1=14.91.

For mature mothers, the sample size is n2=132, the sample mean is 29.15 and the sample standard deviation is s2=13.46.

The difference between means is

M_d=\mu_1-\mu_2=30.7-29.15=1.55

The standard error of the difference between means is

s_M=\sqrt{\dfrac{s_1^2}{n_1}+\dfrac{s_2^2}{n_2}}=\sqrt{\dfrac{14.91^2}{840}+\dfrac{13.46^2}{132}}=\sqrt{ 0.2647+1.3725}=\sqrt{1.6372}\\\\\\s_M=1.2795

Then, the statistic can be calculated as:

z=\dfrac{M_d-(\mu_1-\mu_2)}{s_M}=\dfrac{1.55-0}{1.2795}=1.2114

The P-value for this z-statistic in a two tailed test is:

P-value=2P(z>1.2114)=0.2257

As the P-value is greater than the significance level, the null hypothesis failed to be rejected.

There is no enough evidence to claim that the real average weight gain differs from mature and youger mothers.

5 0
4 years ago
A(n) is a custom or organization with social, educational, or religious purposes.
Mariulka [41]
I think it's C because that's the best answer.
7 0
3 years ago
Read 2 more answers
Mr mistry has 3 grandchildren. He gives Nimisha £m. He gives Sunhil £80 less than Nimisha. He gives Akshay twice as much as Sunh
slamgirl [31]
Here are the variables.

M= nimisha money

S= Sunhil money

A= Akshay money

The expression is S= M-80
A= S*2
M=S+80

Hope this helped

7 0
3 years ago
Read 2 more answers
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