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3 years ago

I need help with my Khan Acadmey work I don’t Understand any of it. Can someone help me Please

Mathematics

1 answer:

ohaa [14]3 years ago

6 0

Answer:

x = 36

Step-by-step explanation:

144 + x = 36

*it's same side interior angles*

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Ratio Question:

netineya [11]

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3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=5%28sin%28t%29%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%2Bycos%28t%29%29%29%3Dcos%28t%29%20%20%28sin%28

Nataliya [291]

Assuming you mean

$5\sin t\dfrac{\mathrm dy}{\mathrm dt}+5y\cos t=\cos t\sin^2t$

This ODE is linear in $y$ , and you can already contract the left hand side as the derivative of a product:

$\dfrac{\mathrm d}{\mathrm dt}\left[5y\sin t\right]=\cos t\sin^2t$

Integrating both sides with respect to $t$ yields

$5y\sin t=\displaystyle\int\cos t\sin^2t\,\mathrm dt$
$5y\sin t=\dfrac13\sin^3t+C$
$y=\dfrac1{15}\sin^2t+C\csc t$

Given that $y\left(\dfrac\pi2\right)=9$ , we have

$9=\dfrac1{15}\sin^2\dfrac\pi2+C\csc\dfrac\pi2$
$9=\dfrac1{15}+C$
$C=\dfrac{134}{15}$

so that the particular solution over the interval is

$y=\dfrac1{15}\sin^2t+\dfrac{134}{15}\csc t$

6 0

3 years ago

The population of kansas city, missouri was 435,000 in 1990 and 482,300 in 2005. if the population is changing linearly, write a

Jlenok [28]

Find the slope of the line connecting (1990,435000) and (2005,482300):

482300-435000 47300
m = ----------------------- = ---------------- = 3153/yr (approx)
2005 - 1990 15 yr

Use the point-slope formula to find the equation of this str. line:

y-435000 = (3153/yr)(x-1990)

The year 2020 is 30 years after 1990. Thus, the expected pop in 2020 is

given by y-435000 = 3153(30) = 94590, so that y = 529590.

4 0

3 years ago