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3 years ago

El área de un rectángulo se calcula multiplicando la longitud de la base por la longitud de su altura.

1 answer:

ioda3 years ago

4 0

<span>Para obtener el otro número, debemos dividir la base por el área. Haciendo eso obtenemos 8.6 Para verificar, multiplicamos 10.4 y 8.6. 10.4 x 8.6 = 89.44

Entonces la respuesta es B.) 8.6</span>

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Find the second derivative y=1/5x^2+1/11x

Amiraneli [1.4K]

$\frac{dy}{dx}=\frac{1}{5}.x^{2-1}.2 + \frac{1}{11}.x^{1-1}.1$

$\frac{dy}{dx}=\frac{2}{5}.x+\frac{1}{11}$

$\frac{d^2y}{dx^2}=\frac{2}{5}.x^{1-1}.1$

$\frac{d^2y}{dx^2}=\frac{2}{5}$

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2 years ago

PLEASE HELPPP! TWO DIFFERENT GRAPHS, TWO DIFFERENT QUESTIONS,

timurjin [86]

Answer:

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#1 = C,D,E

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2 years ago

O terreno da fazenda de Eduardo foi aumentado 2 m na horizontal e 2 m na vertical. Se antes do aumento o terreno tinha o formato

Novay_Z [31]

Answer:

New area of Eduardo's farm after the increase = x² + 4x + 4

Nova área da fazenda de Eduardo após o aumento = x² + 4x + 4

Step-by-step explanation:

English Translation

The land on Eduardo's farm was increased by 2 m horizontally and 2 m vertically. If before the increase the land was shaped like an x-side square, what is the new area after the increases?

Solution

The previous area of Eduardo's farm is the are of a square with side lenght of x.

Area of a square = (side length)² = x²

Then, the land on Eduardo's farm was increased by 2 m horizontally and 2 m vertically.

New horizontal length of Eduardo's farm = (x+2)

New vertical length of Eduardo's farm = (x+2)

New area of Eduardo's farm = (x+2)(x+2)

= x² + 4x + 4

In Portugese/Em português

A área anterior da fazenda de Eduardo é a de um quadrado com comprimento lateral de x.

Área de um quadrado = (comprimento lateral)² = x²

Em seguida, o terreno da fazenda de Eduardo foi aumentado 2 m na horizontal e 2 m na vertical.

Novo comprimento horizontal da fazenda de Eduardo = (x + 2)

Novo comprimento vertical da fazenda de Eduardo = (x + 2)

Nova área da fazenda de Eduardo

= (x + 2) (x + 2) = x² + 4x + 4

Hope this Helps!!!

Espero que isto ajude!!!

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3 years ago

Nine times a number is six thousand three hundred. What is the number

Anvisha [2.4K]

6300/9=700
the answer is 700

7 0

3 years ago

Read 2 more answers

Show that sec(x)-tan(x)sin(x)=cos(x)is an identity for any value of x.

Dmitriy789 [7]

Here is one way to show that the left side is identical to the right side.

$\sec(x)-\tan(x)\sin(x) = \cos(x)\\\\\\\frac{1}{\cos(x)}-\frac{\sin(x)}{\cos(x)}\sin(x) = \cos(x)\\\\\\\frac{1}{\cos(x)}-\frac{\sin^2(x)}{\cos(x)} = \cos(x)\\\\\\\frac{1-\sin^2(x)}{\cos(x)} = \cos(x)\\\\\\\frac{\cos^2(x)}{\cos(x)} = \cos(x)\\\\\\\cos(x)=\cos(x)\\\\\\$

Throughout the entire process, the right hand side stayed the same. When working on identities, it's important to keep one side the same while you transform the other side.

Despite the two sides being identical when simplified, there is the issue of cos(x) being zero in the denominator on the left hand side. Be sure to account for this when forming the domain. No such issue occurs on the right hand side. For instance, the value x = pi/2 leads to a division by zero error when in radian mode. So if I was your teacher, I would revise the "for any value of x" and replace it with something along the lines of "for any x value in the domain".

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2 years ago