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frez [133]
3 years ago
12

El área de un rectángulo se calcula multiplicando la longitud de la base por la longitud de su altura.

Mathematics
1 answer:
ioda3 years ago
4 0

<span>Para obtener el otro número, debemos dividir la base por el área. Haciendo eso obtenemos 8.6 Para verificar, multiplicamos 10.4 y 8.6. 10.4 x 8.6 = 89.44

 Entonces la respuesta es B.) 8.6</span>
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In the figure below, if BE is the perpendicular bisector of AD, what is the value of x?
dedylja [7]

Both sides would be the same, so set them to equal ans solve for x.


3x+4 = 2x +7

Subtract 4 from each side:

3x = 2x +3

Subtract 2x from each side:

x = 3

The answer is X =  3.

4 0
3 years ago
An elephant at the zoo lost 32 pounds over 8 months. The elephant lost the same amount of weight each month. Enter an integer th
inna [77]

Answer:

<em> He would loose 4lbs.  a Month 32/8=4</em>

Step-by-step explanation:

<em>First thing you need to do is to get the months down to one. so you need to divide 32/8 to get the pounds per month</em>

3 0
3 years ago
Read 2 more answers
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3 years ago
Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.
Leviafan [203]

Answer:

Option D. 3.73​

Step-by-step explanation:

we know that

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

and

sin^{2}(\alpha)+cos^{2}(\alpha)=1

step 1

Find cos(X)

we have

sin(x)=\frac{1}{2}

we know that

sin^{2}(x)+cos^{2}(x)=1

substitute

(\frac{1}{2})^{2}+cos^{2}(x)=1

cos^{2}(x)=1-\frac{1}{4}

cos^{2}(x)=\frac{3}{4}

cos(x)=\frac{\sqrt{3}}{2}

step 2

Find tan(x)

tan(x)=sin(x)/cos(x)

substitute

tan(x)=1/\sqrt{3}

step 3

Find sin(y)

we have

cos(y)=\frac{\sqrt{2}}{2}

we know that

sin^{2}(y)+cos^{2}(y)=1

substitute

sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1

sin^{2}(y)=1-\frac{2}{4}

sin^{2}(y)=\frac{2}{4}

sin(y)=\frac{\sqrt{2}}{2}

step 4

Find tan(y)

tan(y)=sin(y)/cos(y)

substitute

tan(y)=1

step 5      

Find tan(x+y)

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

substitute

tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73

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3 years ago
I need help
Jobisdone [24]

Answer:

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