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Sveta_85 [38]
3 years ago
6

What's the solution and answer? And explain please

Mathematics
1 answer:
Advocard [28]3 years ago
7 0
The solution is subtract4.7x on both sides. Then you get -2.2x=7.7. Divide 7.7 by -2.2 and you get x= -3.5
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Find x if y=-3<br> 2x/y+6=-4
igomit [66]
The answer is x = 3.

4 0
3 years ago
The lines shown below are perpendicular. If the green line has a slop of 2/5, what is the slope of the red line?
aivan3 [116]

The slope of the red line that is perpendicular to the green line is: -5/2.

<h3>What are the Slope Values of Perpendicular Lines?</h3>

When one line lies perpendicular to another line, the slope of one must be the negative reciprocal of the other line.

<h3>What is the Negative Reciprocal of a Number?</h3>

If given a number, i.e. a/b, the negative reciprocal of a/b would the opposite value of the reciprocal of a/b.

Reciprocal of a/b is b/a. Negative reciprocal of a/b would therefore be: -b/a.

Given that the slope of the green line is: 2/5. And it is perpendicular to the red line. The slope of the red line would be the negative reciprocal of 2/5.

Negative reciprocal of 2/5 is -5/2.

Therefore, the slope of the red line is: -5/2.

Learn more about slope of perpendicular lines on:

brainly.com/question/1362601

#SPJ1

5 0
1 year ago
Marta walked at 3.3 miles per hour for 0.54 hours. how far did she walk?
Anon25 [30]

This is a proportion, she is walking 3.3 every hour. She walked for 5.4 hours. And we don't know how far she walked so its x/.54. Then you cross multiply which gives you 3.9×.54=x. We multiply those decimals and we get 1.782.

7 0
3 years ago
The given line segment has a midpoint at (3, 1).
Katena32 [7]

Answer:

y=\frac{1}{3}x

Step-by-step explanation:

The given line segment has a midpoint at (3, 1) and goes through (2, 4), (3, 1), and (4, -2). We can use any two of the three points to calculate the equation of the line. Let us use the points (2, 4) and (4, -2)

Therefore the line goes through (2, 4) and (4, -2). The equation of a line passing through (x_1,y_1)\ and\ (x_2,y_2) is:

\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}.

Therefore the line passing through (2, 4) and (4, -2) has an equation:

\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}\\\frac{y-4}{x-2}=\frac{-2-4}{4-2}\\\frac{y-4}{x-2}=\frac{-6}{2}\\y-4=x-2(-3)\\y-4=-3x+6\\y=-3x+10

Comparing with the general equation of line: y = mx + c, the slope (m) = -3 and the intercept on the y axis (c) = 10

Two lines are said to be perpendicular if the product of their slope is -1. If the slope of line one is m1 and the slope of line 2 = m2, then the two lines are perpendicular if:

m_1m_2=-1.

Therefore The slope (m2) of the perpendicular bisector of y = -3x + 10 is:

m_1m_2=-1\\-3m_2=-1\\m_2=\frac{1}{3}

Since it is the  perpendicular bisector of the given line segment, it passes through the midpoint (3, 1). The equation of the perpendicular bisector is:

\frac{y-y_1}{x-x_1}=m\\\frac{y-1}{x-3}=\frac{1}{3}\\ y-1= \frac{1}{3}(x-3)\\ y-1=\frac{1}{3}x-1\\y=\frac{1}{3}x

the equation, in slope-intercept form, of the perpendicular bisector of the given line segment is y=\frac{1}{3}x

7 0
3 years ago
Read 2 more answers
-a^2+46a-480=0<br> a - ?
sattari [20]
a = 30
a = 16

-a² + 46a -480 = 0

(-a + 30) (a -16) = 0
(-a)(a) + (-a)(-16) + 30(a) + 30(-16) = 0
-a² + 16a + 30a -480 = 0
-a² + 46a - 480 = 0

(-a + 30) = 0   ; (a - 16) = 0
-a = -30          ;   a = 16
 a = 30

To check:
a = 30
-(30)² + 46(30) - 480 = 0
-900 + 1380 - 480 = 0
480 - 480 = 0
0 = 0

a = 16
-(16)² + 46(16) - 480 = 0
-256 + 736 - 480 = 0
480 - 480 = 0
0 = 0
5 0
3 years ago
Read 2 more answers
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