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FinnZ [79.3K]
3 years ago
8

Each side of an equilateral triangle measures 9cm. Find the height, h, of the triangle.

Mathematics
1 answer:
lesantik [10]3 years ago
4 0
Heigh \ for\ equilateral \ triangle \ is \calculated\ from\ formula:\\\\h=\frac{\sqrt3}{2}a\\\\a-side\ of\ triangle\\\\a=9cm\\\\h=\frac{\sqrt3}{2}*9=\frac{9\sqrt3}{2}=4,5\sqrt2cm
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Find the sine and cosine of the given angle<br> 120°
SIZIF [17.4K]

Answer:

By using the value of cosine function relations, we can easily find the value of sin 120 degrees. Using the trigonometry formula, sin (90 + a) = cos a, we can find the sin 120 value. We know that the value of cos 30 degrees is √3/2. Therefore, sin 120° = √3/2

Step-by-step explanation:

please mark brainlist

3 0
2 years ago
Will make BRAINLIEST
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Answer:

6

Step-by-step explanation:

maximum calories in a day = 540

no. of calories from the dog food = 320 x 1 \frac{1}{2}

                                                       = 480

∴ she can have:  540 - 480

                          = 60 calories to stay inside calorie range

no. of new treats she can have = 60 ÷ 10

                                                    = 6

Hope this helps!

                       

7 0
2 years ago
Read 2 more answers
Problem Page The price of a notebook was $3.90 yesterday. Today, the price fell to $3.40 . Find the percentage decrease. Round y
OleMash [197]
Always find the difference in prices first. 
<span>3.45 - 3.20 = $.25 difference </span>

<span>Always divide the difference by the original price. Change this number into a per cent. </span>
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6 0
3 years ago
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A shopkeeper had a profit of ₹ 50 on Monday , a loss of ₹ 20 on Tuesday and of loss of
Oliga [24]

Answer:

12

Step-by-step explanation:

Remark

I can't use a symbol for the currency. I'll just get the answer in numbers. You can add the symbol.

Solution

First day: 50

Second day: - 20

Third day: - 18

50 - 20 - 18 = 12

4 0
3 years ago
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Flauer [41]

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\displaystyle\frac{2}{\sqrt{6}}=\frac{2}{\sqrt{6}}\cdot\frac{\sqrt{6}}{\sqrt{6}}\\\\=\frac{2\sqrt{6}}{\sqrt{6}\cdot\sqrt{6}}=\frac{2\sqrt{6}}{6}\\\\=\bf{\frac{\sqrt{6}}{3}}

2. Identify the squares under the radical and remove them.

5\sqrt{12xm^3}=5\sqrt{(4m^2)(3xm)}=5\sqrt{(2m)^2}\sqrt{3xm}\\\\=5\cdot 2m\sqrt{3xm}=\bf{10m\sqrt{3xm}}

7 0
3 years ago
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