1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rosijanka [135]
3 years ago
6

I drove 2 1/2 hour at a constant speed of 60 miles per hour and then for another 30 minutes at a speed of 40 miles per hour how

far did i drive
Mathematics
1 answer:
nekit [7.7K]3 years ago
3 0
60*2= 120

60/2= 30

120+30= 150


40/2= 20

150+20= 170

You drove 170 miles.

I hope this helped!
You might be interested in
What is twelve divided by two fifths
salantis [7]

Answer:

30

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Help me find the slope please guys<br> Im struggling
tatuchka [14]

Answer:

negative 1

Step-by-step explanation:

\frac{y2 - y1}{x2 - x1}  = m

the 2 points: (-2,0), (-3,1)

(1-0)/(-3+2)

=-1

m=-1

brainliest please

7 0
2 years ago
If an hour is 45 years how long is a minute
Ainat [17]
Since one hour = 45 years, one minute should be 1/60th of 45 years because 60 minutes = an hour.

45/60 = 3/4

So one minute would be 3/4 of an hour, or 45 minutes.

Hope this helps!
8 0
2 years ago
Will make bianleast no picture
natita [175]

Answer:  24, 24, 47

<u>Step-by-step explanation:</u>

In order to form a triangle, the sum of two sides must be GREATER than the third side for all combinations.

a + b > c       &       a + c > b        &        b + c > a

23 + 28 = 51 which is NOT greater than 55

15 + 30 = 45 which is NOT greater than  45

8 + 17 = 25 which is NOT greater than 25

24 + 24 > 47      &        24 + 47 > 24       &       24 + 24 > 27

all combinations are true so these side lengths can form a triangle

7 0
2 years ago
Two particles are fixed to an x axis: particle 1 of charge -1.00 x 10-7 C is at the origin and particle 2 of charge +1.00 x 10-7
r-ruslan [8.4K]
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint. 

The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
</span>
Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
6 0
3 years ago
Other questions:
  • Juanita is on vacation and needs a taxi ride
    11·1 answer
  • Canada is the king of the doughnut world, as it has more doughnut shops per capita than any other country in the world. Tim Hort
    8·1 answer
  • 1<br> 4<br> 3<br> In the image above,<br> 23 =<br> 129, what is the value of<br> 22?
    10·1 answer
  • Solve for x. x³ = 216
    8·1 answer
  • Which expression is equal to sec x° multiplied by cot x°?
    12·2 answers
  • Which one of the following measurement represents the longest distance 5m, 10cm, 50mm, 1km
    14·1 answer
  • G(t) = -(t - 1)2 +5<br> What is the average rate of change of g over the interval -4
    7·1 answer
  • The perimeter of a rectangular painting is 340cm. If the width of the painting is 74cm, what is its length?
    6·2 answers
  • Show how to solve a)
    6·1 answer
  • Gordon types 2,584 words in 38 minutes.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!