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2 years ago

Pleasee help meeeeeee

Mathematics

1 answer:

soldier1979 [14.2K]2 years ago

4 0

Step-by-step explanation:

we mulyiply 3*1 =x-7

3=x-7

-x= -7-3

-x= -11 so when we divide -11 by -x it becomes 11

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Rewrite the expression in the form 5^n<br><br> (5^-8) (5^-10)

oee [108]

Answer:

Step-by-step explanation:

This problem is all about bases and exponents. Because we have a quotient and the bases are both 5's, that means that we can use the rule of exponents for quotients to rewrite and simplify:

That's the simplification as long as you are "allowed" to leave the exponent as a negative number.

4 0

2 years ago

Read 2 more answers

I'd appreciate the right answer

shutvik [7]

Answer:

No.

If y is greater than 3, it is not a solution to the system of inequalities. (7,5) has a y value of 5, therefore it is is not a solution.

8 0

2 years ago

Solve 3x^2 + 6x+15=0

Elden [556K]

Answer:

The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )

Step-by-step explanation:

Given equation as :

3 x² + 6 x +15 = 0

The value of x fro the quadratic equation a x² + b x + c = 0 is obtained as

x = $\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$

So , from given eq , the value of x is now obtain as

x = $\frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, x = $\frac{-6\pm \sqrt{6^{2}-4\times 3\times 15}}{2\times 3}$

Or, x = $\frac{\sqrt{-144} }{6}$

∴ x = ( - 1 + 2 i ) , ( - 1 - 2 i )

Hence The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i ) Answer

6 0

3 years ago

The sum of the number times 3 and 15

Anon25 [30]

Answer:

45 should be the answer

3 0

2 years ago

Read 2 more answers

Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund

lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

$\sigma=\sqrt{\frac{p*(1-p)}{n} }$

If n=1139 and p =0.96, the standard deviation is:

$\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836$

The minimum and maximum usual values are:

$\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n$

$\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62$

5 0

2 years ago