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Likurg_2 [28]
4 years ago
5

If angle 1 = 6n + 1 and angle 4 = 4n + 19, what is the angle 2?

Mathematics
1 answer:
kobusy [5.1K]4 years ago
7 0
Angles 1 and 4 are alternate angles and thus have the same measurement. You will set their equations equal to each other and solve for the variable. 

6n + 1 = 4n + 19

Subtract 1 and 4n from both sides to get variables on one side and constants on the other. 

6n - 4n = 19 - 1

Combine like terms and solve for n.

2n = 18
n = 18 / 2
n = 9

Angles 1 and 2 are congruent as labeled in the graph. 

So angle 2 is also 6n + 1

Plug in for 9 for n

6(9) + 1
54 + 1
55

Option C is your answer. 


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The table below shows data from a survey about the amount of time students spend doing homework each week. The students were in
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The correct option is;

Both spreads are best described by the standard deviation

Step-by-step explanation:

The given information are;

,                                    College                       High School

High,                              20                               20

Low,                                6                                 3

Q₁,                                   8                                 5.5

Q₃,                                  18                                16

IQR,                                 10                                10.5

Median,                           14                                11

Mean,                              13.3                             11

σ,                                      5.2                             5.4

Checking for outliers, we have

College

Q₁ - 1.5×IQR gives 8 - 1.5×10 = -7

Q₃ + 1.5×IQR gives 18 + 1.5×10 = 33

For high school

Q₁ - 1.5×IQR gives 5.5 - 1.5×10.5 = -10.25

Q₃ + 1.5×IQR gives 16 + 1.5×10.5 = 31.75

Therefore, there are no outliers and the data is representative of the population

From the data, for the college students, it is observed that the difference between the mean, 13.3 and Q₁, 8, and between Q₃, 18 and the mean,13.3 is approximately the standard deviation, σ, 5.2

The difference between the low and the high is also approximately 3 standard deviations

Therefore the college spread is best described by the standard deviation

Similarly for the high school students, the IQR is approximately two standard deviations, the  difference between the mean, 11 and Q₁, 5.5, and between Q₃, 16 and the mean,11 is approximately the standard deviation, σ, 5.4

Therefore the high school spread is also best described by the standard deviation.

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3 years ago
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