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3 years ago

15

What are the formulas to calculate acceleration A. velocity and time B. displacement and time C. Change in distance and time D.

Change in velocity and time

1 answer:

scZoUnD [109]3 years ago

6 0

The correct choice is A

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Volume of sphere Marcus is using small stone spheres

satela [25.4K]

<h2>Volume of Sphere</h2>

1. What is the radius of the stone sphere?

- To know what is the radius divide is by 2.

$\large \tt 6 \div 2 = 3$

Therefore, the radius of the stone sphere is 3in

2. What is the volume of the stone sphere?

- Using the formula in finding the Volume of Sphere $\tt V = \frac{4}{3}\pi r^3$ to get the answer. Where the volume of the sphere is $\tt\frac{4}{3}\:\:\:\:\pi$ multiplied by the cube of the radius.

$\tt V = \frac{4}{3}\pi r^3$
$\tt V = \frac{4}{3}\times 3.14\times 3in^3$
$\tt V = \frac{4}{3}\times 3.14\times 27in$
$\tt V = \frac{4}{3}\times 84.78in$
$\tt V = \frac{339.12in}{3}$
$\tt V = 113.04in^3$

Therefore, the volume of the stone sphere is 113.04in³

3. Another stone sphere for the garden has a diameter of 10 inches. What is the volume of the stone sphere? Use 3.14 for <em>π</em>, and round to the nearest hundredth.

- Using the formula in finding the Volume of Sphere $\tt V = \frac{4}{3}\pi r^3$ to get the answer. Where the volume of the sphere is $\tt\frac{4}{3}\:\:\:\:\pi$ multiplied by the cube of the radius.

$\tt V = \frac{4}{3}\pi r^3$
$\tt V = \frac{4}{3}\times 3.14\times 5in^3$
$\tt V = \frac{4}{3}\times 3.14\times 125in$
$\tt V = \frac{4}{3}\times 392.5in$
$\tt V = \frac{1570in}{3}$
$\tt V = 523.33in^3$

<h3>Explanation</h3>

Therefore, the volume of the stone sphere is 523.33in³

<h3>#CarryOnLearning</h3>

4 0

2 years ago

Read 2 more answers

Given the system of constraints, name all vertices of the feasible region. Then find the maximum value of the given object funct

Dmitrij [34]

Refer to the figure shown below.

The feasible region that satisfies all the constraints is the shaded region.
The bounding vertices are
A (0, 3)
B (0, 0)
C (5, 0)
D (1.5, 3.5)

All the functions that define the constraints are either linear or constant.
The maximum value is at vertex D, and equal to 3.5.

3 0

3 years ago

Plz no stupid answers .Correct answer will be marked as brainliest.

jeka94

Answer:

x= 5 /2 , − 4

Step-by-step explanation:

Factor and set each factor equal to zero.

3 0

3 years ago

Read 2 more answers

10. Higher Order Thinking One day,

hram777 [196]

126,945 ≈ 100,000 (to the nearest hundred thousand)

126,945 ≈ 130,000 (to the nearest ten thousand)

126,945 ≈ 127,000 (to the nearest thousand)

The amount that is closest to the actual attendance is 127,000

<h3>Rounding numbers</h3>

From the question, we are to round the given number

From the given information,

Total attendance at the state fair was 126,945

We are to round 126,845 to the nearest hundred thousand, nearest ten thousand and nearest thousand

5 is the units digit

4 is the tens digit

9 is the hundreds digit

6 is the thousands digit

2 is the ten thousands digit

1 is the hundred thousands digit

To the nearest hundred thousand

Since to is less than 5, we will round the number down

Thus,

126,945 ≈ 100,000

To the nearest ten thousand

Since 6 is greater than 5, we will round up

126,945 ≈ 130,000

To the nearest thousand

Since 9 is greater than 5, we will round up

126,945 ≈ 127,000

Hence, the amount that is closest to the actual attendance is 127,000

Learn more on Rounding numbers here: brainly.com/question/130699

#SPJ1

7 0

1 year ago

the fourth term of a sequence is 40. write the first 5 terms of two different sequences that satisfy that condition

frez [133]

Answer:

A.P. : 10, 20, 30, 40, 50

G.P. : 5, 10, 20, 40, 80 .

Step-by-step explanation:

It is given that fourth term of a sequence is 40.

It is not given that whether the sequence is A.P. or G.P.

We need to write two different sequences that satisfy the given condition.

For A.P.,

Required sequence : 10, 20, 30, 40, 50

Here, first term is 10, common difference is 10.

For G.P.,

Required sequence : 5, 10, 20, 40, 80

Here, first term is 5, common ratio is 2.

Therefore, the two sequences are 10, 20, 30, 40, 50 and 5, 10, 20, 40, 80 .

4 0

3 years ago