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Law Incorporation [45]
4 years ago
11

Please help with the following algebra question

Mathematics
1 answer:
xxTIMURxx [149]4 years ago
5 0
Hello,
Please, see the attached file.
Thanks.

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If c(x) = 4x − 2 and d(x) = x² + 5x, what is (c.d)(x)?
snow_lady [41]

Answer:

4x^2+20x-2

Step-by-step explanation:

To find (c.g)(x) we basically use the function d(x) as your variable, x, and plug it into c(x). So we replace every x in c(x) with the function d(x), x^{2} +5x

c(g(x))=4(x^{2} +5x)-2

c(g(x))4x^2+20x-2

6 0
2 years ago
Micheal was asked to give examples of the identity property of addition and identity multiplication. Below are his answers.
xxMikexx [17]

Answer:

identity property of addition-

a+0=a

identity property of multiplication-

a*1=a

Step-by-step explanation:

i cant give u an exact answer as u didnt give Micheals answers so i just gave some examples about what addition and multiplication identity property should look like. Identity property's concept is to keep the same identity. Basically, "a" shouldnt change. In addition, to keep a the same all u hv to do is add 0 as anything plus 0 is the same. for multiplication, just multiply by 1. Hope this helps!!

5 0
3 years ago
Solve for C:<br> Spam: deiodhwidweiudjegydjwe
Maksim231197 [3]

Answer:

C=\frac{5F-160}{9}

Step-by-step explanation:

Let's solve for C.

F=\frac{9C}{5}

Step 1: Flip the equation.

\frac{9}{5} C+32=F

Step 2: Add -32 to both sides.

\frac{9}{5} C+32+-32=F+-32

\frac{9}{5}C=F-32

Step 3: Divide both sides by \frac{9}{5}.

\frac{\frac{9}{5}C}{\frac {9} {5}}=\frac{F-32}{\frac{9}{5} }

C=\frac{5F-160}{9}

Answer:

C=\frac{F-160}{9}

8 0
3 years ago
Please answer thank u ASAP.
Neko [114]

Answer:

a?

Step-by-step explanation:

7 0
3 years ago
An elephant can run of a mile in 36 seconds. At this rate, which expression can be used to determine how fast an elephant runs i
Mice21 [21]

<u>Answer:</u>

The expression that can be used to determine how fast an elephant runs in miles per hour is 100 miles per hour

<u>Solution:</u>

Given that,

Distance covered by an elephant in 36 seconds is equal to 1 mile

Therefore, <em>distance covered by the elephant in 1 second</em> is  \frac{1}{36} mile

Therefore, <em>distance covered by the elephant in 60 seconds</em> (60 seconds = 1 minute) is

\frac{1}{36} \times 60=\frac{5}{3} \text { miles }

Therefore, <em>distance covered by the elephant in 60 minute</em> (60 minute = 1 hour) is

\frac{5}{3} \times 60=100 \text { miles per hour }

Hence the expression that can be used to determine how fast an elephant runs in miles per hour is 100 miles per hour

7 0
3 years ago
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