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SVETLANKA909090 [29]
3 years ago
10

About 17% of Americans have blue eyes. There are 85 students at Park Street Middle School who have blue eyes. How many total stu

dents would there need to be at Park Street Middle School for the percentage of students with blue eyes to match the national statistic? Please show your work
*Please give me an answer no later than 8:00 on 4/7/16. Thank you!
Mathematics
1 answer:
Lerok [7]3 years ago
4 0
85 divided by 17=5 so every 1% of students at the school comprise of 5 students, to find the total number of students we need to multiply 100 by 5 making 500, so there would be 500 students at park street middle school for the number of students with blue eyes to match the national statistic.
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4) Which linear inequality represents the solution set graphed?
horsena [70]

Answer:

D)€÷√€€$&7$&7$&dy+&"&_

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3 years ago
The accompanying data represent the daily​ (for example, Monday to​ Tuesday) movement of Johnson​ & Johnson​ (JNJ) stock for
egoroff_w [7]

Supposing that the stock increases in 37 days, the 95% confidence interval for the proportion of days JMJ stock increases is: (0.484, 0.7292)

  • The lower bound is of 0.484.
  • The upper bound is of 0.7292.
  • The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

Supposing that it increases on 37 out of 61 days:

n = 61, \pi = \frac{37}{61} = 0.6066

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 - 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.484

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 + 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.7292

The ​95% confidence interval for the proportion of days JMJ stock increases is (0.484, 0.7292), in which 0.484 is the lower bound and 0.7292 is the upper bound.

The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

A similar problem is given at brainly.com/question/16807970

4 0
2 years ago
If x=-1\3 is a zero of a polynomial p(x)=27xcube -axsquare -x+3 then find the value of a
antoniya [11.8K]

Answer:

a = 21

Step-by-step explanation:

If x = h is a zero of a polynomial then f(h) = 0, thus

p(- \frac{1}{3} ) = 27( - \frac{1}{3} )³ - a(- \frac{1}{3} ) - (- \frac{1}{3} ) + 3 = 0, that is

27 (- \frac{1}{27} ) - \frac{1}{9} a + \frac{1}{3} + 3 = 0

- 1 - \frac{1}{9} a + \frac{10}{3} = 0 ( multiply through by 9 to clear the fractions )

- 9 - a + 30 = 0

- a + 21 = 0 ( subtract 21 from both sides )

- a = - 21 ( multiply both sides by - 1 )

a = 21

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2 years ago
Katie has 36 coins in her jar (nickels, dimes, and quarters) totalling $4.20. She has twice as many dimes as quarters. How many
Diano4ka-milaya [45]

Answer:

I think you need to mutply those. And you will get your answer.

Step-by-step explanation:

4 0
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ted took a trip to china. upon leaving he decided to convert all his Yuan back into dollars. how many dollars did he receive if
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Ted would receive 2 dollars
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