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Vesna [10]
3 years ago
8

How would the expression x^3-8 be written using difference of cubes

Mathematics
2 answers:
antoniya [11.8K]3 years ago
6 0

a^3 - b^3 = (a - b)(a^2 + ab + b^2)

x^3 - 8 =

= x^3 - 2^3

= (x - 2)(x^2 + x(2) + 2^2)

= (x - 2)(x^2 + 2x + 4)

Answer: (x - 2)(x^2 + 2x + 4)

ludmilkaskok [199]3 years ago
4 0

we can use formula

a^3-b^3=(a-b)(a^2+ab+b^2)

we can compare

we get

a=x

b=2

now, we can plug that in formula

and we get

x^3-2^3=(x-2)(x^2+2x+2^2)

now, we can simplify it

x^3-8=(x-2)(x^2+2x+4)...........Answer

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Zeros in the denominator that aren't in the numerator are vertical asymptotes.

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a) (0.555, 0) and (6, 0)

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The m(r)-intercept is (0, 1.235).

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3 years ago
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