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just olya [345]
3 years ago
7

I’m literally begging someone please help (just number 10. show work)

Mathematics
1 answer:
Sladkaya [172]3 years ago
6 0

Answer:

h =  \frac{2A}{b +B }

Height= 16 feet

Step-by-step explanation:

Please see attached picture for full solution.

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Rickey has 7 over 8 cup of cereal in a bowl. He then gave two 1 over 4 cups of cereal from his bowl to his little sister. Which
NeX [460]

Answer:

5/8 cup left

Step-by-step explanation:

7/8 - 1/4

1/4=2/8

7/8-2/8

5/8

5 0
2 years ago
One hour after yolanda started walking from x to y, a distance of 45 miles, bob started walking along the same road from y to x.
Rufina [12.5K]
<span>Answer: When bob starts walking The distance between them is 45-3 = 42 miles If they meet at time t then Yolanda would have walked X/3 minutes and Bob would have walked (42-X)/4 mins X/3 = (42-X)/4 so X = 18 Bob would have walked 42-18 = 24 miles.</span>
3 0
3 years ago
Find sin D sin E cos D and cos E
Andrew [12]

9514 1404 393

Answer:

  sin(D) = cos(E) = (√3)/2

  cos(D) = sin(E) = 1/2

Step-by-step explanation:

The mnemonic SOH CAH TOA is intended to remind you of the relationships between trig functions and right triangle sides.

  Sin = Opposite/Hypotenuse

  Cos = Adjacent/Hypotenuse

For this diagram, this means ...

  sin(D) = cos(E) = (13√3)/26 = (√3)/2

  cos(D) = sin(E) = 13/26 = 1/2

5 0
2 years ago
A delivery person uses a service elevator to bring boxes of books up to an office. The delivery person weighs 140 lb and each bo
Sindrei [870]

Answer:He can bring up 13.8333333333 boxes each trip

Step-by-step explanation:

970-140= 830

830÷60=13.8333333333

5 0
3 years ago
A rubber ball is dropped from the top of a hole. Exactly 20 seconds later, the sound of the rubber ball hitting bottom is heard.
gayaneshka [121]

9514 1404 393

Answer:

  4192.9 ft

Step-by-step explanation:

We assume your falling-distance formula is supposed to be ...

  s = 16t²

So, the time required to fall distance s is ...

  t = √(s/16) = (1/4)√s

The time required for sound to travel distance s is ...

  s = 1100t

  t = s/1100

Then the sum of the time for the ball to fall and the time for the sound to travel back is ...

  (1/4)√s + s/1100 = 20

  275√s = 22000 -s . . . . . multiply by 1100 and subtract s

  75625s = s^2 -44000s +484,000,000 . . . square both sides

  s^2 -119,625s +484,000,000 = 0 . . . . put in standard form

  s ≈ (1/2)(119,625 ±√12,374,140,625) = {4192.943, 115432.057}

Only the smaller of these two solutions makes any sense in this problem.

The hole is about 4192.9 feet deep.

_____

<em>Additional comment</em>

The distance equation for the falling object presumes a vacuum. The sound transmission presumes the presence of air, so the question setup is self-contradictory.

7 0
3 years ago
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