All categories

2 years ago

How do I solve this? x/3 + x^2 + 2x^2 - x/3

Mathematics

1 answer:

Anna11 [10]2 years ago

3 0

Answer:

3x²

Step-by-step explanation:

$\frac{x}{3} + x^{2} +2x^{2} -\frac{x}{3}$ =

$x^{2} +2x^{2}$ =

$3x^{2}$

You might be interested in

Consider this sequence: -81, -54, -36, -24, … . The sequence is . The common ratio of the sequence is . The sum of the first fiv

hichkok12 [17]

We have the following remark
-81/-54= -54/-36 = -36/ -24=...= 1.5
the sequence is geometric sequence
the common ratio of the sequence is 1.5
the sum of the five terms of the sequence is
S5= a[1- (1.5)^5 / 1-1.5], a first term,
S5= -42*6.5= - 276

3 0

3 years ago

Read 2 more answers

PLEASE ANSWERRRRRRR

Mademuasel [1]

Answer:

Step-by-step explanation:sorry

8 0

3 years ago

Find the area of the shaded region. use 3.14 for pi.

stepan [7]

Answer:

$18 0 - 60 = 120 \\ \\ \frac{120}{360} \times \pi {r}^{2} \\ \frac{1}{3} \times 3.14 \times 4 \times 4 \\ = 16.75 {u}^{2}$

Answer B is correct.

8 0

3 years ago

What property is -4 + (-3/7)+(-4/7)+7

gizmo_the_mogwai [7]

The answer is 2 but i'm not really sure about it

8 0

3 years ago

Read 2 more answers

The figure below shows a trapezoid, ABCD, having side AB parallel to side DC. The diagonals AC and BD intersect at point O.

Harlamova29_29 [7]

Answer:

Length of BO is three times the length of DO.

Step-by-step explanation:

In trapezoid ABCD, $CD\ ||\ AB$

In ΔCDO and ΔABO,

$m\angle CDO=m\angle ABO$ (Alternate interior angles)
$m\angle DCO=m\angle BAO$ (Alternate interior angles)

So, $\Delta CDO\sim \Delta ABO$ according to Angle-Angle similarity.

Therefore, the ratio of corresponding sides will be same.

$\Rightarrow \dfrac{OD}{OB}=\dfrac{OC}{OA}$

$\Rightarrow \dfrac{OD}{OB}=\dfrac{OC}{3\cdot OC}$

$\Rightarrow \dfrac{OD}{OB}=\dfrac{1}{3}$

$\Rightarrow OB=3\cdot OD$

5 0

3 years ago

Read 2 more answers