Answer:
Answer is A: place absorbent chemical packets in the camera cover
Explanation:
Keith is required to carry adequate gear while going for a shoot. And in this case, he should carry anything that will protect his camera from the ocean and rainwater. By anything, I mean anything that Keith will use to stay dry. Using an air conditioner would be the worst idea. An air conditioner might blow the air towards your camera. Placing the camera in its case will ensure that it is dry and Keith will keep on shooting. Placing absorbent chemical packets in the camera cover will ensure that any water droplets that might fall on the cover of the camera will be absorbed. The point here is to keep dry.
Answer:
The reasons for Blue Screen Of Death are as following:-
- Faulty Memory.
- Power Supply Issue.
- Overheating of Components.
- Malfunctioning Hardwares.
- Poorly coded device drivers.
- Hardware runnign beyond it's capacity.
- Bugs in the Operating System Kernel.
These are the some of the reasons why the blue screen of death is caused.
Answer:
B. CAD produces designs that are of the highest quality.
C. CAD provides systems for error-free manufacturing.
Explanation:
B. CAD produces designs that are of the highest quality.
CAD does produce the highest quality of design, way better than what traditional paper plans can do.
C. CAD provides systems for error-free manufacturing.
Many manufacturing systems can read CAD designs directly before the need of a human intervention in between, that eliminates possible errors.
Answers A and D are not true, because once passed the learning-curve, CAD greatly accelerates the production of designs. And we know the learning-curve is behind them because the question says he has adopted the new system.
Answer:
- public static String bothStart(String text1, String text2){
- String s = "";
-
- if(text1.length() > text2.length()) {
- for (int i = 0; i < text2.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }else{
- for (int i = 0; i < text1.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }
- }
Explanation:
Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).
<em />
Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).
There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).
If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.
The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>
<em />
At the end, return the s as output (Line 21).
