Answer:
CLS
INPUT"Enter any three numbers";a,b,c
IF a>b AND a>c THEN
PRINT a;"is the greatest"
ELSEIF b>a AND b>c THEN
PRINT b;"is the greatest"
ELSE
PRINT c;"is the greatest"
ENDIF
END
Answer:
the answer is D Smart Object
The technology is being used when you are sent an email saying you can track your package is known to be a scan code.
<h3>What are code-scanning technology?</h3>
This is known to be called a barcode reader or simply say a barcode scanner.
It is seen as a kind of an optical scanner that tends to read printed barcodes, as well as be able to decode the data that are found in the barcode and transmit the data to a computer.
Hence, The technology is being used when you are sent an email saying you can track your package is known to be a scan code.
Learn more about scan code from
brainly.com/question/24937533
#SPJ1
A float data type can hold a decimal number.
Answer:
This solution is implemented in C++
void makePositive(int arr[]){
int i =0;
while(arr[i]!=0){
if(arr[i]<0){
arr[i] = abs(arr[i]);
}
i++;
}
i = 0;
while(arr[i]!=0){
cout<<arr[i]<<" ";
i++;
}
}
Explanation:
This defines the function makePositive
void makePositive(int arr[]){
This declares and initializes i to 0
int i =0;
The following iteration is repeated until the last element in the array
while(arr[i]!=0){
This checks if current array element is negative
if(arr[i]<0){
If yes, it changes it to positive
arr[i] = abs(arr[i]);
}
The next element is then selected
i++;
}
This sets i to 0
i = 0;
The following iteration prints the updated content of the array
<em> while(arr[i]!=0){
</em>
<em> cout<<arr[i]<<" ";
</em>
<em> i++;
</em>
<em> }
</em>
}
See attachment for full program which includes the main
