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dimaraw [331]
3 years ago
14

PLEASE HELP, LAST THING I NEED TO GRADUATE

Mathematics
1 answer:
Mice21 [21]3 years ago
7 0
For a), wouldn't you multiply the cost of a twin by the quantity of a twin beige (N) and the cost of a queen by the quantity of the queen beige (N) and then the cost of the king by the quantity of the king beige (N) for CN and do the same thing but with the south quantities? 
And then for b), it's just comparing which one had the most money and find the difference... 
And then C), would be relatively self explanatory where CN would be the potential profit in N and CS would be the potential profit in S and then CN+CS would be the potential profit total? 

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Answer:

n = 18

Step-by-step explanation:

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Suppose~that~the~number~is~x.\\According~to~question,\\x^2-140=3x\\or, x^2-3x-140=0\\From~the~quadratic~formula,\\x = \frac{-(-3)+\sqrt{(-3)^2-4(1)(-140)} }{2(1)} ~and ~x= \frac{-(-3)-\sqrt{(-3)^2-4(1)(-140)} }{2(1)} \\or, x = \frac{3+\sqrt{9+560} }{2}~and~x=\frac{3-\sqrt{9+569} }{2}\\or, x = \frac{3+\sqrt{569} }{2}~and~x=\frac{3-\sqrt{569} }{2}\\So,~the~required~negative~number~is~\frac{3-\sqrt{569} }{2}.

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