(1) The train travels 4 miles per gallon.
(2) The slope of the graph is 
Explanation:
(1) The miles that train travels per gallon is given by

Dividing, we have,

Thus, the train travels 4 miles per gallon.
(2) To determine the slope, let us consider two points from the graph.
The coordinates are
and 
Thus, substituting the coordinates in the slope formula, we get,

Simplifying, we have,

Thus, the slope of the graph is 
Answer:
46,350
Step-by-step explanation:
3% of 45,000 is 1,350
So, 45,000 + 1350 = 46,350
Answer:
Ratio is 1:5; there are 5 times more blue marbles so there should be 10 blue marbles
Step-by-step explanation:
7:35 creates a 1 green marble to every 5 blue marbles ratio. So for every green marble there are 5 blue marbles. If you have 2 green marbles then you have 5+5 blue marbles
The number of mole of pure 11C (carbon-11) initially present is 0.2727 mole
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation
Mole = mass / molar mass
With the above formula, we can obtain the number of mole of pure 11C. Detail below:
<h3>How to determine the mole of 11C</h3>
From the question given, the following data were obtained:
- Molar mass of 11C = 11 g/mol
- Mass of 11C = 3 g
- Mole of 11C =?
Mole = mass / molar mass
Mole = 3 / 11
Mole = 0.2727 mole
Therefore, the number of mole of pure 11C initially present is 0.2727 mole
Learn more about mole:
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We can set this problem up as an algebraic equation, which we can then solve to find our answer.
We start at -3. So we can start our equation with that:

However, this doesn't represent any change in temperature, just that we start at -3. To show change, we will use the variable
, where
stands for the number of hours. Each hour accounts for a change of -2.5 in degrees, meaning that we must multiply our
by -2.5. We can now add this term into our equation:

We are trying to find when we will reach -18 degrees, so we will set our entire equation equal to -18 and solve:



It will take us 6 hours, or choice A.