Question

Terry has a number cube that is numbered from 1 to 6. She rolls the cube 50 times. Which equation can be used to predict the number of times that she will roll a number that is greater than 4?

Answer 1

Terry has a number cube that is numbered from 1 to 6. She rolls the cube 50 times. Which equation can be used to predict the number of times that she will roll a number that is greater than 4?

THE ANSWER IS 2/6(50)

Answer 2

Answer:

$f(r)=^{50}C_r( \frac{1}{3})^r (\frac{2}{3})^{n-r}$

Step-by-step explanation:

Total outcomes : {1,2,3,4,5,6} =6

Favorable outcomes = greater than 4 = {5,6}=2

So, probability of getting a number greater than 4 : $\frac{2}{6}$

Thus the probability of success is $\frac{2}{6}=\frac{1}{3}$

Probability of failure = $1-\frac{1}{3}$

                                 = $\frac{2}{3}$

Now to find the equation we will use formula:

$f(r)=^nC_rp^r q^{n-r}$

Since we are given that  She rolls the cube 50 times.

So, n = 50

p = probability of success =  $\frac{1}{3}$

q = probability of failure =  $\frac{2}{3}$

Substitute the values in the formula :

$f(r)=^{50}C_r( \frac{1}{3})^r (\frac{2}{3})^{n-r}$

Thus equation can be used to predict the number of times that she will roll a number that is greater than 4 is $f(r)=^{50}C_r( \frac{1}{3})^r (\frac{2}{3})^{n-r}$