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gavmur [86]
2 years ago
8

Happy Monday Everybody Free 100 points no joke

Mathematics
2 answers:
vlabodo [156]2 years ago
5 0

Answer:

Thank you

Step-by-step explanation:

Have a great day :D

KIM [24]2 years ago
5 0

Answer:

... =)

Step-by-step explanation:

hope you have a happy week

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Bethany wears jeans every 2 day. She wears running shoes every 3 days. If she wears jeans and running shoes on may 1st what are
andriy [413]
You would find the multiples 2 and 3 had in common
so may 6th, 12th, and 18th
2:   3:
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3 years ago
Which of the following is not one of Euclid’s postulates?
kifflom [539]

I think you forgot to list the following.

5 0
3 years ago
What is the value of x?
uranmaximum [27]

<em>x = 41 cm</em>

<u><em>Here is why:</em></u>

For this question we have to use the pythagorean theorem, which is used for right triangles. The hypotenuse will always be the last in this theorem.

a^2+b^2=c^2

Plug in.

9^2+40^2=c^2

81+1,600=c^2

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\sqrt{1,681}

= 41 cm

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3 years ago
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7 0
3 years ago
Advertisements for the Sylph Physical Fitness Center claim that completion of their course will result in a loss of weight (meas
MrMuchimi

Answer:

90% confidence interval for the mean weight loss for the population represented by this sample assuming that the differences are coming from a normally distributed population is [1.989 ,13.5105]

Step-by-step explanation:

The data given is

                        Mean                 Std Dev

Before            177.25                29.325

After              169.50                    22.431

Difference        7.75                    8.598

Hence d`=   7.75 and sd=   8.598

The 90% confidence interval for the difference in means for the paired observation is given by

d` ± t∝/2(n-1) *sd/√n

Here  t∝/2(n-1)=1.895  where n-1= 8-1= 7 d.f

and  ∝/2= 0.1/2=0.05

Putting the values

d` ± t∝/2(n-1) *sd/√n

7.75  ±1.895 *  8.598 /√8

 7.75  ± 5.7605

1.989 ,13.5105

90% confidence interval for the mean weight loss for the population represented by this sample assuming that the differences are coming from a normally distributed population is [1.989 ,13.5105]

3 0
3 years ago
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