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Greeley [361]
3 years ago
9

What is the difference between an objective statement and a nonobjective statement

Mathematics
1 answer:
Bumek [7]3 years ago
5 0

Answer:

The lack of observable evidence

Step-by-step explanation:

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(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim
aleksklad [387]

(i) Given that

V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

Compute the integral:

V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr

V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R

V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)

V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0
3 years ago
Determine the value of x.
stellarik [79]
It is B 4.4
Because of 2.2 is the first one and the second one should be 4.4 so it B. 4.4
3 0
3 years ago
Use (a) the Trapezoidal Rule, (b) the Midpoint Rule, and (c) Simpson’s Rule to approximate the given integral
malfutka [58]

Answer:

10.294935

Step-by-step explanation:

i typed numbers

7 0
4 years ago
A section in a stained glass window is shaped like a trapezoid. The top base is 2 centimeters and the bottom base is 4.5 centime
Elza [17]

Answer:

2.8 cm

Step-by-step explanation:

The area of a trapezoid is calculated using the formula:

A=\frac{(B+b)h}{2}

where

B is the length of the major base

b is the length of the minor base

h is the height of the trapezoid

In this problem, the glass window has the shape of a trapezoid. We know that:

B = 2 cm is the length of the top base

b = 4.5 cm is the length of the bottom base

A=9.1 cm^2 is the area of the trapezoid

Solving for h, we can find the height of the stained glass window:

h=\frac{2A}{B+b}=\frac{2(9.1)}{2+4.5}=2.8 cm

8 0
3 years ago
Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p
rusak2 [61]

Answer:

DNE

Step-by-step explanation:

Given that two particles travel along the space curves

r_1(t) = (t, t^2, t^3)\\ r_2(t) = (1 + 2t, 1 + 6t, 1 + 14t )

To find the points of intersection:

At points of intersection both coordinates should be equal.

i.e. r1 =r2

Equate corresponding coordinates

t=1+2t\\t^2=1+6t\\t^3=1+14t

I equation gives t =-1

Substitute in II equation to get t^2 = -5

i.e. t cannot be real

Hence no point of intersection

DNE

8 0
3 years ago
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