The equation given in the question is
3x^2 + 22x - 16 = 0
3x^2 + 24x - 2x - 16 = 0
3x(x + 8) - 2(x + 8) = 0
(3x - 2)(x + 8) = 0
Then either
3x - 2 = 0
3x = 2
x = 2/3
Or
x + 8 = 0
x = - 8
So from the above deduction, we can conclude that the value of "x" cam be either 2/3 or - 8.
Answer:
The answer is 18
Step-by-step explanation:
Add 8
C) 44, 52, 60
.................
Answer:
Step-by-step explanation:
We can answer this in two ways: Differentiation and Graphing.
<u>Differentitate:</u>
The first derivative of a function yields a function that provides the slope for any point on the line of the original function. The slope of a vertex is zero, so we can set the first derivative to 0 and solve for x.
f(x) = 3(x-1)^2 + 4
f(x) = 3(x-1)(x-1) + 4
f(x) = 3(x^2 - 2x + 1) + 4
f(x) = 3x^2 - 6x + 7
f'(x) = 6x -6
Set this = 0 and find x:
0 = 6x -6
x = 1
The value of y when x=1 in the original equation is:
f(1) = 3(1-1)^2 + 4
y = 4
The vertex is (1,4)
<u>Graph:</u>
You can use DESMOS to plot the function. The result is attached. Look for the vertex and read the coordinates. (1,4) seems to work.