Answer: Since you didn't include the picture, I can give you the description so you know how to pick the correct answer.
The third quartile of a data is always shown in a box plot. In the middle of your graph should be a box. The third quartile is the value that goes with the far right edge of the box.
Answer:
* = b²
Step-by-step explanation:
You know that the square of a binomial is of the form ...
(x + y)² = x² + 2xy + y²
Matching given terms, we have ...
49 = y²
2xy = 14b
Solving the first of these relations for y, we have
y = √49 = 7
Putting that in the second relation and solving for x, we find ...
2x·7 = 14b
14x = 14b
x = b
Then the first term of the expansion, x², will be b².
The missing term is b².
Answer:
1) 
2) ![\sqrt[3]{y^5}=y^{\frac{5}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E5%7D%3Dy%5E%7B%5Cfrac%7B5%7D%7B3%7D)
3) ![\sqrt[5]{a^{12}}=a^{\frac{12}{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Ba%5E%7B12%7D%7D%3Da%5E%7B%5Cfrac%7B12%7D%7B5%7D%20%7D)
4) ![\sqrt[4]{z^{9}}=z^\frac{9}{4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bz%5E%7B9%7D%7D%3Dz%5E%5Cfrac%7B9%7D%7B4%7D)
Step-by-step explanation:
1) 
We know that 
So,
2) ![\sqrt[3]{y^5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E5%7D)
We know that ![\sqrt[3]{x}=x^{\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B3%7D)
So,
3) ![\sqrt[5]{a^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Ba%5E%7B12%7D%7D)
We know that ![\sqrt[5]{x}=x^{\frac{1}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B5%7D)
So,
4) ![\sqrt[4]{z^{9}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bz%5E%7B9%7D%7D)
We know that ![\sqrt[4]{x}=x^{\frac{1}{4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B4%7D)
So,
Answer: f⁻¹(x)=2x-6
Step-by-step explanation:
To find the inverse of an equation, you replace y with x and x with y. Then, you solve for y.
y=1/2x+3 [replace y with x and x with y]
x=1/2y+3 [subtract both sides by 3]
x-3=1/2y [multiply both sides by 2]
y=2(x-3) [distribute]
y=2x-6
Now, we know the inverse function is f⁻¹(x)=2x-6.
