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Irina-Kira [14]
3 years ago
10

A man standing at a window 5 meters tall watches a falling ball pass by the window in 0.3 seconds. From how high above the top o

f the window was the ball released?
Mathematics
1 answer:
kogti [31]3 years ago
4 0

Answer:

11.76 meters.

Step-by-step explanation:

To carry out the problem it is necessary to take into account the following equations:

The first, in relation to the initial and final velocity, we know that gravity is 9.81 m / s ^ 2 and that the time is 0.3 seconds.

Vf = Vo + g * t = Vo + 9.81 * 0.3

Vf = Vo + 2.94 (1)

The second, in the same way relating the initial and final speed, also with gravity but this time with the distance S, which we know to be 5 meters.

Vf ^ 2 = Vo ^ 2 + 2 * g * S

Vf ^ 2 = Vo ^ 2 + 2 * 9.81 * 5

Vf ^ 2 = Vo ^ 2 + 98.1 (2)

Now, we have two equations with two unknowns. If we replace (1) in (2):

(Vo + 2,943) ^ 2 = Vo ^ 2 + 98.1

Vo ^ 2 + 5,886 * Vo + 8.66 = Vo ^ 2 + 98.1

Vo ^ 2 is canceled and we have, and reorganizing, we have:

Vo = 89.44 / 5.886

Vo = 15,195 m / s

Now with the following formula we will calculate the height

Vo ^ 2 = 2 * g * h

h = Vo ^ 2 / (2 * g) = (15,195 ^ 2) / (2 * 9.81) = 11.76 meters

In other words, the height corresponds to 11.76 meters.

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Schach [20]

Answer:

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Step-by-step explanation:

We observe that first differences of the given numbers are ...

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That is, each difference is 2× the previous one. This suggests an exponential relation that has a base of 2.

We notice that doubling a term doesn't give the next term, but gives a value that is 4 less than the next term. So, we can get the next term by doubling the previous one and adding 4.

Then our recursive relation is ...

  f[1] = 3 . . . . the first term

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The next term is 2·52 +4 = 108.

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Step-by-step explanation:

The triangle that is shown is a 45-45-90 triangle, so we know that GH = GJ = 9 and IJ = 13, we are able to solve for HI.

Technically, IJ = HI, since both triangles are congruent. Both IJ and HI will be 13.

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