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Answer:
Written in Python
def sums(n):
total = 0
for i in range(1,n+1):
if i%2 == 0:
total = total + i*2
else:
total = total + i
return(total)
Step-by-step explanation:
The function is written in Python
def sums(n):
This initializes total to 0
total = 0
This iterates through the integers that makes up n i.e. 1,2,3.....n
for i in range(1,n+1):
This checks if current digit is even
if i%2 == 0:
If yes, it adds the double of the digit
total = total + i*2
else:
If otherwise, it adds the digit
total = total + i
This prints the calculated sum or total
return(total)
To call the function from main, use the following:
print(sums(n))
Where n is a positive integer. i.e.
Answer:
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 67
Variance = 3.85
We have to find 80% confidence interval for the population variance of the weights.
Degree of freedom = 67 - 1 = 66
Level of significance = 0.2
Chi square critical value for lower tail =
Chi square critical value for upper tail =
80% confidence interval:
Putting values, we get,
Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.
The first step to solve this problem is to convert the first mixed number to an improper fraction.
÷ 3 + 
Dividing is equivalent to multiplying with the reciprocal value,, so next you will need to change the signs.
x +
Multiply the fractions
+
Finally,, add the two fractions together to get your final answer
This means that the correct answer to your question is .
Let me know if you have any further questions
:)
Dividing is equivalent to multiplying with the reciprocal value,, so next you will need to change the signs.
Multiply the fractions
Finally,, add the two fractions together to get your final answer
This means that the correct answer to your question is
Let me know if you have any further questions
:)