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Vladimir79 [104]
3 years ago
7

The parks department is creating a walkway to run through a park. The park, in the shape of a square, measures 300 feet on each

side. The walkway will be constructed along the diagonal of the square. How much concrete will be needed to create the walkway?
Mathematics
1 answer:
const2013 [10]3 years ago
7 0

Answer:

<h2>4 x 3 =    1200</h2>

Step-by-step explanation

there is a square and it has 4 sides and if each are 300 you have to multiply  but remember to put the 2 zeros cause 300 has 2 zeros

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Can someone help me find the measure of each angle in the triangle?
Cerrena [4.2K]

Answer:Remember -- the sum of the degree measures of angles in any triangle equals 180 degrees. ... So, the measure of angle A + angle B + angle C = 180 degrees. ... If a triangle is equilateral, what is the degree measure of each of its angles?

Step-by-step explanation:

8 0
3 years ago
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A cone has radius 9 and height 12. A frustum of this cone has height 4.
Rom4ik [11]

The radii of the frustrum bases is 12

Step-by-step explanation:

In the figure attached below, ABC represents the cone cross-section while the BCDE represents frustum cross-section

As given in the figure radius and height of the cone are 9 and 12 respectively

Similarly, the height of the frustum is 4

Hence the height of the complete cone= 4+12= 16 (height of frustum+ height of cone)

We can see that ΔABC is similar to ΔADE

Using the similarity theorem

AC/AE=BC/DE

Substituting the values  

12/16=9/DE

∴ DE= 16*9/12= 12

Hence the radii of the frustum is 12  

3 0
3 years ago
Let f(x)=x^2+5x-8. What is the average rate of change from x = 2 to x = 6? Enter the answer in the box ___
koban [17]

Answer:

13

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [2, 6 ]

f(b) = f(6) = 6² + 5(6) - 8 = 36 + 30 - 8 = 58

f(a) = f(2) = 2² + 5(2) - 8 = 4 + 10 - 8 = 6

Hence

average rate of change = \frac{58-6}{6-2} = \frac{52}{4} = 13

5 0
3 years ago
Find the area of the following polygon:
Masja [62]

Given:

ABCD is a quadrilateral

AC = 12, DE = 4 and FB = 5

To find:

The area of the polygon.

Solution:

AC bisects the quadrilateral into two triangles.

Area of triangle:

$A=\frac{1}{2}\times\text{base}\times\text{height}

<u>Area of triangle DAC:</u>

$A=\frac{1}{2}\times AC \times DE

$A=\frac{1}{2}\times 12 \times 4

A=24

Area of triangle DAC = 24 square units.

<u>Area of triangle BAC:</u>

$A=\frac{1}{2}\times AC \times FB

$A=\frac{1}{2}\times 12 \times 5

A=30

Area of triangle BAC = 30 square units.

Area of polygon = Area of triangle DAC + Area of triangle BAC

                           = 24 square units + 30 square units

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3 0
3 years ago
2x-9 x=3 ..............................
WINSTONCH [101]

Answer:

3

Step-by-step explanation:

g

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3 years ago
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