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nirvana33 [79]
3 years ago
14

Help please

Mathematics
1 answer:
nika2105 [10]3 years ago
3 0

Answer:

The correct option is Option D) A=-0.7,B=-9/16,C=-0.4,D=-5/16

Step-by-step explanation:

Consider the provided number line.

From the number line we can observed that:

1) A, B, C and D lies between -1 and 0.

2) Point A and B lies between -1 and -0.5

3) Point C and D lies between -0.5 and 0

Therefore, the value of A and B must have a negative value lying between -1 and -0.5

Also, the value of C and D must have a negative value lying between -0.5 and 0.

Now consider the provided options.

Option A) A=-5/16,B=-9/16,C=-0.7,D=-0.4

This is Incorrect representation because the value of C and D should lying between -0.5 and 0.

Option B) A=-0.4,B=-0.7,C=-5/16,D=9/16

This is Incorrect representation because the value of A and B should lying between -1 and -0.5.

Option C) A=9/16,B=-5/16,C=-0.4,D=-0.7

This is Incorrect representation because the value of C and D should lying between -0.5 and 0.

Option D) A=-0.7,B=-9/16,C=-0.4,D=-5/16

A = -0.7\\B = -\displaystyle\frac{9}{16} = -0.5625\\C = -0.4\\D = -\frac{5}{16} = -0.3125

Here the value of A and B lying between -1 and -0.5 also the value of C and D lying between -0.5 and 0.

Also they are in ascending order from -1 to 0.

Hence, the correct option is Option D) A=-0.7,B=-9/16,C=-0.4,D=-5/16

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3 years ago
According to Harper's Index, 40% of all federal inmates are serving time for drug dealing. A random sample of 20 federal inmates
loris [4]

Answer:

(a) P(X≥10) = 0.245

(b) P(X≤5) = 0.125

(c) The expected number of inmates who are serving time for drug dealing is 8.

Step-by-step explanation:

We will use the binomial distribution to solve this problem. Let X be the number of federal inmates who are serving time for drug dealing. We will use the binomial probability formula:

P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ

where n = total number of federal inmates

           x = no. of federal inmates who serve time for drug dealing

           p = probability that a federal inmate is serving time for drug dealing

           q = probability that a federal inmate is not serving time for drug dealing

(a) P(X≥10) = 1 - P(X<10)

                 = 1 - [P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5) + P(X=6) + P(X=7) + P(X=8) + P(X=9)]

                = 1 - [²⁰C₀(0.4)⁰(0.6)²⁰⁻⁰ + ²⁰C₁(0.4)¹(0.6)²⁰⁻¹ + ²⁰C₂(0.4)²(0.6)²⁰⁻² + ²⁰C₃(0.4)³(0.6)²⁰⁻³ + ²⁰C₄(0.4)⁴(0.6)²⁰⁻⁴ + ²⁰C₅(0.4)⁵(0.6)²⁰⁻⁵ + ²⁰C₆(0.4)⁶(0.6)²⁰⁻⁶ + ²⁰C₇(0.4)⁷(0.6)²⁰⁻⁷ + ²⁰C₈(0.4)⁸(0.6)²⁰⁻⁸ + ²⁰C₉(0.4)⁹(0.6)²⁰⁻⁹

                 = 1 - (0.000036 + 0.00048 + 0.00308 + 0.0123 + 0.0349 + 0.0746 + 0.1244 + 0.1658 + 0.1797 + 0.1597)

                 = 1 - 0.7549

P(X≥10) = 0.245

(b) P(X≤5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)

since we have calculated these values in the previous part, we will simply plug them in here and then add them up.

P(X≤5) = 0.000036 + 0.00048 + 0.00308 + 0.0123 + 0.0349 + 0.0746

P(X≤5) = 0.125

(c) For a binomial distribution, the expected value can be calculated as:

μ = np

  = (20)(0.4)

μ = 8

The expected number of inmates who are serving time for drug dealing is 8.

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